<?xml version="1.0" encoding="UTF-8"?>
<User>
    <Age>23</Age>
    <NameList>
        <name>name1</name>
        <name>name2</name>
        <name>name3</name>
        <name>name4</name>        
    </NameList>
</User>

public class User {
    
    private int age;
    
    private List nameList;
}

            File file= new File(xmlFileName);

            DocumentBuilderFactory ch =                                 DocumentBuilderFactory.newInstance();
            DocumentBuilder db = ch.newDocumentBuilder() ;
            Document dom = db.parse(file) ;
            NodeList nl_sr = dom.getElementsByTagName("source-rightCode");

------解决方案--------------------
其实就是解析xml文件，然后赋值给你的bean对象。

用什么解析方式得看你的具体需求

------解决方案--------------------
Java code
import com.thoughtworks.xstream.*;
import com.google.common.io.*;
import com.google.common.base.*;
public class Main {
    public static void main(final String[] args) throws Exception{
        XStream xstream = new XStream();
        xstream.alias("User",User.class);
        xstream.aliasField("Age",User.class,"age");
        xstream.aliasField("NameList",User.class,"nameList");
        xstream.alias("name",String.class);
        
        User user = (User)xstream.fromXML(Resources.toString(Resources.getResource(Main.class,"user.xml"),Charsets.UTF_8));
        System.out.println(xstream.toXML(user));
    }
}

------解决方案--------------------
最后一句的输出是
XML code
<User>
  <Age>23</Age>
  <NameList>
    <name>name1</name>
    <name>name2</name>
    <name>name3</name>
    <name>name4</name>
  </NameList>
</User>

------解决方案--------------------
simple-xml 的话

Java code
@ElementList(name="NameList",entry="name")
private List<String> nameList;

------解决方案--------------------
xstream 也有 annotation ，功能好像比api弱多了。

Java code
@XStreamAlias("Age")
private int age;