import java.io.*;
public class Czhb
{
    public static void main(String[] args)throws Exception
    {
        int t=System.in.read();

       System.out.println(t);
       
    }    
}

import java.util.Scanner;
public class Czhb{
    public static void main(String[] args){
        Scanner in=new Scanner(System.in);
        int t=in.nextInt();
        System.out.println(t);
    }
}

------解决方案--------------------
通用的方法：
Java code

import java.io.*;

public class Test{
        public static  void main(String[] args){
            try{
                BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
                System.out.print("请输入:");
                String s = br.readLine();
                System.out.println(s);
            }catch(IOException e){
                    e.printStackTrace();
                }
            }
    }

------解决方案--------------------
import java.io.*;

public class Test{
       public static  void main(String[] args){
           try{
               BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
               System.out.print("请输入:");
               String s = br.readLine();
               System.out.println(s);
           }catch(IOException e){
                   e.printStackTrace();
               }
           }
   }


同意4楼

------解决方案--------------------
没有强制转化吧？读入的默认是STRING， 而你这样是不行的。
Java code
import java.io.*;
//最多算到25的阶乘
public class test 
{
    public static void main(String[] args)throws IOException
    {
        //System.out.println("输入一个数， 算");
        BufferedReader buf;
        buf = new BufferedReader(new InputStreamReader(System.in));
        String str;
        int x;
        
        while(true)
        {
            str = buf.readLine();
            if(str.equals("quit"))   
                break;
            x = Integer.parseInt(str);
            System.out.println(x + "的阶乘是：" + fact(x));
        }
    }
    
    static long fact(int k)
    {
        long result = 1;
        for(int i = 2; i <= k; ++i)
        {
            result *= i;
        }
        return result;
    }
}

------解决方案--------------------
这个是ASCII码值