List<Integer> list = new ArrayList<Integer>();
    Scanner sc = new Scanner(System.in);
    boolean flag = true;
    while(flag){
        Integer temp = sc.nextInt();
        if(temp == 0){
        flag = false;
        }
        list.add(temp);
    }
    int gtZero = 0;
    int sum = 0;
    for(Integer i : list){
        if(i > 0){
        gtZero ++;
        sum += i;
        }
    }
    System.out.println("大于零的个数:" + gtZero);
    System.out.println("总和:" + sum);

------解决方案--------------------
2、
Java code

 public static void change(double args[], int i, double param){
    if(args != null){
        for(int index1=0; index1<args.length; index1++){
        if(index1 == i){
            for(int index2=args.length - 1; index2>=index1; index2--){
            args[index2] = args[index2-1]; 
            }
            args[index1] = param;
        }
        }
        for(double temp : args){
        System.out.println(temp);
        }
    }
    }

------解决方案--------------------
Java code

import java.util.Scanner;

public class Test6 {
    public static void main(String[] args){
        int count = 0;
        int sum = 0;
        Scanner sc = new Scanner(System.in);
        int tmp = sc.nextInt();
        while(tmp != 0){
            if(tmp>0){
                count++;
                sum += tmp;
            }
            tmp = sc.nextInt();
        }
        System.out.println(count+"  "+sum);
    }
}

------解决方案--------------------

Java code

//[个人意见，供参考]
class Main
{
    public static void main(String [] args)
    {        
        //编译运行时的格式：javac Main.java
        //                      java Main 1 2 3 -4 -5 6 0
        
        //1.使用args接收输入数据，
        int count=0;
        int value=0;
        int len=0;
        for(int i=0;i<args.length-1;i++)
        {
            
                if((len=args[i].toCharArray()[0])>'0')
                {
                    count++;
                    value=value+(len-48);
                    System.out.println((len-48));
                }
        }
        System.out.println("个数为:"+count+"，和为:"+value+"\r\n");
        
        //2.需要新建一数组，且比原数组length大1
        double [] d1 ={1.0,2.0,3.0,4.0,5.0};
        int i=4;
        double d2=8.0;
        method(d1,i,d2);
    }
    
    public static void method(double[] d1,int i,double d2)
    {
            double [] dou=new double[d1.length+1];
            for(int j=0;j<dou.length;j++)
            {
                    if(j<i)
                        dou[j]=d1[j];
                    else if(j==i)
                        dou[j]=d2;
                    else
                        dou[j]=d1[j-1];
            }
            for(int j=0;j<d1.length;j++)
            {
                System.out.print(d1[j]+" ");
            }
            System.out.println();
            for(int j=0;j<dou.length;j++)
            {
                System.out.print(dou[j]+" ");
            }
    }
}