日期:2014-05-20  浏览次数:20841 次

关于对象序列化小例子的2个小问题。
请看注释问题。
Java code
import java.io.*; 

public class ObjectTest implements Serializable {
static private int a;            //问题1:static 和 transient的字段不是不能序列化的吗?(这在jdk ObjectOutputStream类中有说过)
static String s;

// public ObjectTest(){System.out.println("Constructor");}  //问题2:我把默认的构造器注释起来居然也能运行(这在jdk Serializable接口中有说过)
public ObjectTest(int a, String s){
this.a = a;
this.s = s;
}

// private void writeObject(java.io.ObjectOutputStream out)throws IOException{
// out.writeInt(a);
// out.writeObject(s);
// }
//
// private void readObject(java.io.ObjectInputStream in)throws IOException,ClassNotFoundException{
// a = in.readInt();
// s = (String)in.readObject();
// }

public String toString(){
return "a = " + a + ",  s = " + s;
}
public static void main(String[] args)throws IOException, ClassNotFoundException{
ObjectTest ot = new ObjectTest(1, "a");
System.out.println("Test one:");
System.out.println(ot);

BufferedOutputStream bos = new BufferedOutputStream(
new FileOutputStream("D:\\333\\OOO.test"));
ObjectOutputStream oos = new ObjectOutputStream(bos);
oos.writeObject(ot);
oos.close();

BufferedInputStream bis = new BufferedInputStream(
new FileInputStream("D:\\333\\OOO.test"));
ObjectInputStream ois = new ObjectInputStream(bis);
ObjectTest ot2 = (ObjectTest)ois.readObject();
ois.close();

System.out.println("Test two:");
System.out.println(ot2);
}
}


------解决方案--------------------
新年快乐,帮你顶一下。
------解决方案--------------------
我说下问题一吧
静态和transient域在对象被序列化时会被跳过
就是说这些域不会被写入
下面是一个例子
transient int a未被写入
Java code

import java.io.*;
import java.util.*;

public class Test implements Serializable
{
    public transient int a;
    
    public Test(){ }
    
    public static void main(String[] args)
    {
        Test t = new Test();
        t.a = 10;
        System.out.println("t.a = " + t.a);
        
        try
        {
            ObjectOutputStream out = new ObjectOutputStream(new FileOutputStream("t.dat"));
            out.writeObject(t);
            out.close();
            
            ObjectInputStream in = new ObjectInputStream(new FileInputStream("t.dat"));
            Test nt = (Test)in.readObject();
            in.close();
            
            System.out.println("nt.a = " + nt.a);
        }
        catch(Exception e){e.printStackTrace();}
    }
}

------解决方案--------------------
第一个问题。static 和 transient的字段事实上并没有序列化。
反序列化输出的是类的值。
如果该成这样
Java code

oos.close();
[color=#FF0000]ObjectTest.a=2;[/color]   
BufferedInputStream bis = new BufferedInputStream(
              new FileInputStream("D:\\333\\OOO.test"));

------解决方案--------------------
static的数据没有被序列化。之所以你的测试看起来好像是被序列化了,原因是static的数据在内存中使用都是只有一份,你把代码改称下面这样子

 public static void main(String[] args)throws IOException, ClassNotFoundException{
ObjectTest ot = new ObjectTest(1, "a");
System.out.println("Test one:");
System.out.println(ot);

BufferedOutputStream bos = new BufferedOutputStream(
new FileOutputStream("D:\\333\\OOO.test"));
ObjectOutputStream oos = new ObjectOutputStream(bos);