import java.io.*;
import java.util.*;
import java.text.*;
public class DateInFile{
    public static void main(String[] args){
        File file = new File("D:/train/csdn/date.txt");
        try{
        BufferedWriter bw = new BufferedWriter(new FileWriter("D:\\train\\csdn\\date.txt"));        
        SimpleDateFormat sdf = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
        Date d = new Date();
        String msg = sdf.format(d);
        bw.write(msg);
        bw.flush();
System.out.println(msg+"已写入文件！");
        bw.close();
        BufferedReader buf = new BufferedReader(new FileReader("D:\\train\\csdn\\date.txt"));
        String s = buf.readLine();
        Date dd = sdf.parse(s);
System.out.println(dd+"已从文件取出！");
        buf.close();
        }
        catch(Exception e){
            e.printStackTrace();
        }
    }
}

------解决方案--------------------
只是把当前日期取出，然后格式化成特定形式的字符串，
然后就是IO操作。

------解决方案--------------------
楼上朋友回答的不错，楼主参考一下

------解决方案--------------------
mark

------解决方案--------------------
探讨

Java codeimport java.io.*;
import java.util.*;
import java.text.*;
public class DateInFile{
    public static void main(String[] args){
        File file = new File("D:/train/csdn/date.txt");
        try{
        BufferedWriter bw = new BufferedWriter(new FileWriter("D:\\train\\csdn\\date.txt"));        
        SimpleDateFormat sdf = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
       …


------解决方案--------------------
2楼 答案不错 就是IO的操作 以及 date的 format

------解决方案--------------------
2楼正解阿。。。很详细

------解决方案--------------------
探讨

Java codeimport java.io.*;
import java.util.*;
import java.text.*;
public class DateInFile{
    public static void main(String[] args){
        File file = new File("D:/train/csdn/date.txt");
        try{
        BufferedWriter bw = new BufferedWriter(new FileWriter("D:\\train\\csdn\\date.txt"));        
        SimpleDateFormat sdf = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
       …


------解决方案--------------------
1楼的好像不对吧，parse方法怎么返回是String类型呢

------解决方案--------------------
可以参考一下2楼的

------解决方案--------------------
C#代码，
using System;
using System.Collections.Generic;
using System.Text;
using System.IO;
using System.Windows.Forms;
using System.Runtime.InteropServices;

namespace ConvertUnicodeToByte
{
   class IniFile
   {  
       static void Main(string[] args)
       {
           string riqi = "";
           string path = "";
           riqi = System.DateTime.Now.ToString("yyyy-MM-dd HH:mm:ss ");
           //path = Application.StartupPath + "timedate.ini";
           path = @"C:\Documents and Settings\Administrator\My Documents\Visual Studio 2005\Projects\ConvertUnicodeToByte\ConvertUnicodeToByte\bin\Debug\timedate.ini";