大家来讨论下这个面试题
写一个程序，从文件（c:\test.txt）中查出字符串”zhuobin”出现的次数？
  （要求：用最简洁的方法，写出符合上面要求的程序）

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String类的indexOf递归遍历就可以实现 我觉得 不过效率就不是很好了
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public int findNumOfStringInFile(String filePath,String str)throws Exception{
BufferReader br = new BufferReader(new FileReader(new File(filePath)));
String line = null;
int num = 0;
while(line=br.readLine()!=null){
String[] s = line.split(str);
if(s.length()>1)
num+=s.length-1;
}
return num;
}

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探讨

public int findNumOfStringInFile(String filePath,String str)throws Exception{
BufferReader br = new BufferReader(new FileReader(new File(filePath)));
String line = null;
int num = 0;
while(line=br.readLine()!=null){
String[] s = line.split(str);
if(s.length()>1)
num+=s.length-1;
}
return num;
}

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不会写
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BufferedReader in = new BufferedReader(new FileReader("c:\\test.txt"));
String s = "";
int num = 0;
while ((s = in.readLine()) != null) {
if (line.indexOf("zhuobin") > 0) ++num;
}

return num;

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探讨

public int findNumOfStringInFile(String filePath,String str)throws Exception{
BufferReader br = new BufferReader(new FileReader(new File(filePath)));
String line = null;
int num = 0;
while(line=br.readLine()!=null){
String[] s = line.split(str);
if(s.length()>1)
num+=s.length-1;
}
return num;
}

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探讨

万一那个单词换行了怎么办？

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探讨

BufferedReader in = new BufferedReader(new FileReader("c:\\test.txt"));
String s = "";
int num = 0;
while ((s = in.readLine()) != null) {
if (line.indexOf("zhuobin") > 0) ++num;
}

return num;

------解决方案--------------------
同上,如果是查"zhuobin"的词的话,就不能用indexof 了.可能会有"sb_zhuobin"这样的存在
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不追求效率的话 indexof可以·


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探讨

引用:
public int findNumOfStringInFile(String filePath,String str)throws Exception{
BufferReader br = new BufferReader(new FileReader(new File(filePath)));
String line = null;
int num = 0;
while(line=br.readLine()!=null){
String[] s = line.split(str);
if(s.length()>1)
num+=s.length-1;
}
return num;
}

这个没创意  哈哈哈哈

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探讨

引用:
引用:
public int findNumOfStringInFile(String filePath,String str)throws Exception{
BufferReader br = new BufferReader(new FileReader(new File(filePath)));