变量初始化的问题
代码如下:
DatagramSocket socket;
try{
  socket=new DatagramSocket(port);
}
catch(SocketException e){
  System.out.println("Failed to define DatagramSocket object.");
}
...
socket.send(packet);
编译提示:
variable socket might not have been initialized
  ^
我把try catch块去掉,编译提示:
unreported exception java.net.SocketException; must be caught or declared to be thrown
socket=new DatagramSocket(port);
  ^
1 error
不知如何才能解决?

------解决方案--------------------
DatagramSocket socket = null; 

------解决方案--------------------

Java code

DatagramSocket socket = null;
try{ 
    socket=new   DatagramSocket(port); 
} 
catch(SocketException   e){ 
    System.out.println( "Failed   to   define   DatagramSocket   object. "); 
} 
... 
socket.send(packet);

------解决方案--------------------
如果你的程序中try{}catch{}抛出异常的话，那么socket将不能被初始化，而你在socket.send(packet)中用到了这个没有初始化的变量所以楼上的是正解