撼动正则表达式天地?!
谁能给出下面正确的解呢
如下的代码，如何用正则表达式正确的去除注释:
var   kk   =   "//   sljdfljsdf ";   //   *skldflsfllk "sdlf//sdfdsf "
var   kk   =   "//   sljdfljsdf ";   //   *skldflsfllk "sdlf//sdfdsf "
var   kk   =   "//   sljdfljsdf ";   //   *skldflsfllk "sdlf//sdfdsf "
var   kk   =   "//   sljdf/*sdf*/ljsdf ';   //   *sk/*fdsf*/ld " "flsfllk "sdlf//sdfdsf "
var   kk   =   '//   sljdf/*sdf*/ljsdf ';   //   *sk/*fdsf*/ld " "flsfllk "sdlf//sdfdsf "
var   kk   =   '//   sljdf/*sdf*/ljsdf ';   //   *sk/*fdsf*/ld " "flsfllk "sdlf//sdfdsf "

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mark
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不明白！// 后面的不都是注释吗？
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关键是 "的处理，呵呵
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kk.replace(/^\/\/\\*w+$/, ' ');
不知道行不！！！
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正则表达式如下：
//(? <=;\s*//)[^\n]+
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楼上的就可以,以分号为分界点.
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js不支持反向预搜索
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不懂,顶一下.
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我想问一下，弄这个有什么用吗？
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感觉是很闲的问题
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不会
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呃....我什么都不懂...
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<span id= "text " style= "display:none ">
<pre>
var kk = "// sljdfljsdf "; // *skldflsfllk "sdlf//sdfdsf "
var kk = "// sljdfljsdf "; // *skldflsfllk "sdlf//sdfdsf "
var kk = "// sljdfljsdf "; // *skldflsfllk "sdlf//sdfdsf "
var kk = "// sljdf/*sdf*/ljsdf ' // *sk/*fdsf*/ld " "flsfllk "sdlf//sdfdsf "
var kk = '// sljdf/*sdf*/ljsdf '; // *sk/*fdsf*/ld " "flsfllk "sdlf//sdfdsf "
var kk = '// sljdf/*sdf*/ljsdf ' // *sk/*fdsf*/ld " "flsfllk "sdlf//sdfdsf "
var kk = new Object(); //test
</pre>
</span>

<script>
var reg = /([^ ' "\/\n]*([ ' "]?).*?[^\\]\2(?:\s*;\s*|\s+))(?:\/\/.*|\/\*.*\*\/\s*)(\n|$)/g;
var kk = document.getElementById( "text ").innerText;
alert( "处理前：\n " + kk);
alert( "处理后：\n " + kk.replace(reg, "$1$3 "));
</script>
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程序员群 41801837
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http://community.csdn.net/Expert/topic/5541/5541735.xml?temp=.7890283