再来一题 。。都问的没分了。。55
Assuming   that   the   serializeBanana2()   and   the   deserializeBanana2()
methods   will   correctly   use   Java   serialization   and   given:
13.   import   java.io.*;
14.   class   Food   {Food()   {   System.out.print(”1”);   }   }
15.   class   Fruit   extends   Food   implements   Serializable   {
16.   Fruit()   {   System.out.print(”2”);   }   }
17.   public   class   Banana2   extends   Fruit   {   int   size   =   42;
18.   public   static   void   main(String   []   args)   {
19.   Banana2   b   =   new   Banana2();
20.   b.serializeBanana2(b);   //   assume   correct   serialization
21.   b   =   b.deserializeBanana2(b);   //   assume   correct
22.   System.out.println(”   restored   “+   b.size   +   “   “);   }
23.   //   more   Banana2   methods
24.   }
What   is   the   result?
A.   Compilation   fails.
B.   1   restored   42
C.   12   restored   42
D.   121   restored   42
E.   1212   restored   42
F.   An   exception   is   thrown   at   runtime.

答案D

可以解释下么。。谢谢。。

------解决方案--------------------
我只贴一段：
If you are a serializable class, but your superclass is NOT serializable, then any instance variables you INHERIT from that superclass will be reset to the values they were given during the original construction of the object. This is because the non-serializable class constructor WILL run!