java Method种试用
日期：2014-05-20 浏览次数：20794 次
背景：在项目中有一堆javabean，要用在界面上画一堆tableview，要对这一堆tableview进行排序，因此要写一堆sorter类（假如为每个tableview都写一个的话），工作量比较大。
??????? 思考：其实这些sorter类都是差不多的，只是调用的javabean不同，方法名称不同，实现的原理，没有什么不同，那么该如何使用一个sorter类就可对所有的tableview进行排序呢？
??????? 思考结果：也许可以用Class类与Method类，也就是什么reflect机制。
??????? 困难：从来没用过reflect机制。
?????? 没有过，没关系。JDK5.0文档与google是我最好的老师。
?????? 下面就是我的成果了：
?????? 第一步，先建个javabean：
package?test;
public?class?Model?{
????private?String?id;????private?String?name;????private?String?description;????
????public?Model()?{????????id?=?"id";????????name?=?"name";????????description?=?"description";
????}????public?String?getId()?{????????return?id;????}????public?void?setId(String?id)?{????????this.id?=?id;????}????public?String?getName()?{????????return?name;????}????public?void?setName(String?name)?{????????this.name?=?name;????}????public?String?getDescription()?{????????return?description;????}????public?void?setDescription(String?description)?{????????this.description?=?description;????}
}
??????? 第二步：package?test;import?java.lang.reflect.InvocationTargetException;import?java.lang.reflect.Method;public?class?TestMethodReflect?{????public?static?final?String?ID?=?"Id";????public?static?final?String?NAME?=?"Name";????public?static?final?String?DESCRIPTION?=?"Description";????//方法名集合????public?static?final?String[]?ALL?=?{?ID,?NAME,?DESCRIPTION?};????//这是测试数据????public?static?final?String[]?MODELDATA?=?{?"1",?"Gavin",????????????"this?is?model's?test?data"?};????/**?????*?@param?args?????*/????public?static?void?main(String[]?args)?{????????try?{????????????//获得Model类????????????Class?model?=?Class.forName("test.Model");????????????//获得Model类的实例????????????Object?object?=?model.newInstance();????????????for?(int?i?=?0;?i?<?ALL.length;?i++)?{????????????????//获得Model类的set方法，参数为String类型????????????????Method?setMethod?=?model.getMethod("set"?+?ALL[i],?String.class);????????????????//调用set方法????????????????setMethod.invoke(object,?MODELDATA[i]);????????????????//获得Model类的get方法，无参数????????????????Method?getMethod?=?model.getMethod("get"?+?ALL[i],?null);????????????????//调用get方法，并输出数据????????????????System.out.println(getMethod.invoke(object,?null));????????????}????????}?catch?(ClassNotFoundException?e)?{????????????//?TODO?Auto-generated?catch?block????????????e.printStackTrace();????????}?catch?(SecurityException?e)?{????????????//?TODO?Auto-generated?catch?block????????????e.printStackTrace();????????}?catch?(NoSuchMethodException?e)?{????????????//?TODO?Auto-generated?catch?block????????????e.printStackTrace();????????}?catch?(IllegalArgumentException?e)?{????????????//?TODO?Auto-generated?catch?block????????????e.printStackTrace();????????}?catch?(IllegalAccessException?e)?{????????????//?TODO?Auto-generated?catch?block????????????e.printStackTrace();????????}?catch?(InvocationTargetException?e)?{????????????//?TODO?Auto-generated?catch?block????????????e.printStackTrace();????????}?catch?(InstantiationException?e)?{????????????//?TODO?Auto-generated?catch?block????????????e.printStackTrace();????????}????}}
??????? ok，大功告成！
??????? 成功后的思考：我只要在一个sorter类里添加一个classname的参数，添加一个methodName的参数（类型为String[]），用一个for循环就有可能用一个sorter类为每个tableview加入排序的功能。
