关于java常量存储方式的问题，大家帮忙看一下
最近学习java，有个String的小问题请教一下大伙，大家帮忙看一下！
String str=new String("Hello");
System.out.prinln(str.length());//输出为5
本人查了一下String的源码，有如下几个构造方法：
public String(String original) {
int size = original.count;
char[] originalValue = original.value;
char[] v;
  if (originalValue.length > size) {
  // The array representing the String is bigger than the new
  // String itself. Perhaps this constructor is being called
  // in order to trim the baggage, so make a copy of the array.
  int off = original.offset;
  v = Arrays.copyOfRange(originalValue, off, off+size);
  } else {
  // The array representing the String is the same
  // size as the String, so no point in making a copy.
v = originalValue;
  }
this.offset = 0;
this.count = size;
this.value = v;
  }


 public String(char value[]) {
int size = value.length;
this.offset = 0;
this.count = size;
this.value = Arrays.copyOf(value, size);
  }

public int length() {
  return count;
  }
对于str.length()，返回的是Count的值即字符串的长度，我想问的是对于new String("Hello")调用的是哪个构造方法，如果调用的是String(String original)，那么在这个函数中Hello的长度是怎么来的，编译器如何解释这部分，大虾们帮忙看一下！！！

------解决方案--------------------
调用的肯定是String(String original)
int size = original.count;
this.count = size;
这两句就是把长度赋值了啊