日期:2014-05-17  浏览次数:20677 次

(急)jsp上传压缩文件并到服务器端能自动解压
上传压缩文件我可以实现了,就是不知道怎么让压缩文件在指定的目录(即文件上传到的目录)下解压,请大家帮忙!
有代码最好了,呵呵,在线等。。。。

------解决方案--------------------
1 你会解压缩吗?
2 既然会,那么把上传的文件保存成文件,然后解开不就行了!

------解决方案--------------------
java.unil.zip.ZipFile
解压
------解决方案--------------------
Java code

import java.io.File;
import java.io.FileInputStream;
import java.io.FileOutputStream;
import java.util.zip.ZipEntry;
import java.util.zip.ZipInputStream;
import java.util.zip.ZipOutputStream;

public class TestZip {

    public void zip(String zipFileName, String inputFile) throws Exception {
        zip(zipFileName, new File(inputFile));
    }

    public void zip(String zipFileName, File inputFile) throws Exception {
        ZipOutputStream out = new ZipOutputStream(new FileOutputStream(zipFileName));
        zip(out, inputFile, "");
        System.out.println("zip done");
        out.close();
    }

    public void unzip(String zipFileName, String outputDirectory)
            throws Exception {
        ZipInputStream in = new ZipInputStream(new FileInputStream(zipFileName));
        ZipEntry z;
        while ((z = in.getNextEntry()) != null) {
            System.out.println("unziping " + z.getName());
            if (z.isDirectory()) {
                String name = z.getName();
                name = name.substring(0, name.length() - 1);
                File f = new File(outputDirectory + File.separator + name);
                f.mkdir();
                System.out.println("mkdir " + outputDirectory + File.separator
                        + name);
            } else {
                File f = new File(outputDirectory + File.separator
                        + z.getName());
                f.createNewFile();
                FileOutputStream out = new FileOutputStream(f);
                int b;
                while ((b = in.read()) != -1)
                    out.write(b);
                out.close();
            }
        }
        in.close();
    }

    public void zip(ZipOutputStream out, File f, String base) throws Exception {
        System.out.println("Zipping  " + f.getName());
        if (f.isDirectory()) {
            File[] fl = f.listFiles();
            out.putNextEntry(new ZipEntry(base + "/"));
            base = base.length() == 0 ? "" : base + "/";
            for (int i = 0; i < fl.length; i++) {
                zip(out, fl[i], base + fl[i].getName());
            }
        } else {
            out.putNextEntry(new ZipEntry(base));
            FileInputStream in = new FileInputStream(f);
            int b;
            while ((b = in.read()) != -1)
                out.write(b);
            in.close();
        }

    }

    public static void main(String[] args) {
        try {
            TestZip t = new TestZip();
            t.zip("D:/zip.zip", "D:/zip");
            t.unzip("D:/zip.zip", "D:/newZip");
        } catch (Exception e) {
            e.printStackTrace(System.out);
        }
    }

}

------解决方案--------------------
import java.io.File;
import java.io.FileInputStream;
import java.io.FileOutputStream;
import java.util.ArrayList;
import java.util.zip.ZipEntry;
import java.util.zip.ZipInputStream;

public class ZipToFile {


public static boolean zipToFile(String sZipPathFile, String sDestPath) {
boolean flag = false;
try {
  
FileInputStream fins = new FileInputStream(sZipPathFile);
  
ZipInputStream zins = new ZipInputStream(fins);
ZipEntry ze = null;
byte ch[] = new byte[256];
while ((ze = zins.getNextEntry()) !=