日期:2014-05-20 浏览次数:20727 次
public class Test { public static void main(String[] args) { String str = "114"; System.out.println(str.matches("^(0|114)")); } }
String regex = "^(" + "[1-9]" + // 个 "|" + "[1-9]\\d" + // 十 "|" + "[1-9]\\d{3,}" + // 千以上 "|" + "[2-9]\\d{2}" + // 2xx-9xx "|" + "1[02-9]\\d" + // 10x,12x-19x "|" + "11[0-35-9]" + // 110-113,115-119 ")$"; for (int i = 0; i < 10000; i++) { String str = i+""; if (!str.matches(regex) && i != 0 && i != 114) { throw new Exception(str); } }
------解决方案--------------------
String str = "0s14dfd22"; Pattern p = Pattern.compile("[^0,114]+"); Matcher m = p.matcher(str); while(m.find()) { System.err.println(m.group()); }