Scanner console = new Scanner(System.in);
      String val = console.next();
      int n = 0;
      
      try {
         n = Integer.parseInt(val);
      }
      catch(Exception e) {
         n = (int) Float.parseFloat(val);
      }
      
      for(int i = 0; i <= n; i++) {
         System.out.print("[" + i + "] ");
      }

------解决方案--------------------
探讨

Java code

      Scanner console = new Scanner(System.in);
      String val = console.next();
      int n = 0;
      
      try {
         n = Integer.parseInt(val);
      }
      catch(Excep……


------解决方案--------------------
Java code
public static void main(String args[]) {
        
        Scanner console = new Scanner(System.in);
        String s = console.next();
        int n = 0;
        try{
            if(s.matches("[0-9]*[.]{1}[0-9]*")){//小数
                double d = Double.parseDouble(s);
                n = (int) d;
            }else if(s.matches("[0-9]*")){//整数
                n = Integer.parseInt(s);
            }
        }catch(Exception e){
            
        }
        for (int i = 0; i <= n; i++) {
            System.out.print("[" + i + "] ");
        }
    }

------解决方案--------------------
import java.io.*;
public class printNumber {
public static void main(String[] args){
printNumbers();
}

public static void printNumbers(){
	System.out.println("输入截至数据这里必须是整数");//如果这里给的输入错误不是整数那么程序则无法运行，得做一个什么呢？？
	InputStreamReader isr = new InputStreamReader(System.in);
	BufferedReader br = new BufferedReader(isr);
	String str;
	try {
			str = br.readLine();
			int n = (int)Float.parseFloat(str);
			for(int i=0;i<=n;i++)
			{
			System.out.print("["+i+"] ");
			}
		} catch (Exception e) {
			// TODO Auto-generated catch block
			e.printStackTrace();
		}

	}
}
希望对你有用。。。

------解决方案--------------------
for example
Java code
public static void printNumbers(){
    while (true) {
        System.out.println("输入截至数据这里必须是整数/输入[quit]退出程序");
         Scanner console=new Scanner(System.in);
        String data = console.nextLine();
        int n = 0;
        try {
            if ("quit".equals(data)) {
                System.out.println("退出程序。");
                break;
            }
            n = Integer.parseInt(data);
        } catch (Exception e) {
            System.out.println("输入非法数据，请重试。");
            continue;
        }
        for(int i=0;i<=n;i++)
        {
            System.out.print("["+i+"] ");
        }
    }
}