日期:2014-05-16 浏览次数:20365 次
由于项目中使用到了jqgrid组建以及ajax的异步提交等,有时候可能会需要后台往前台返回的是一个json格式的结果。因此我引入了jsonplugin-0.32的jar包。
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json插件提供了一个“json”结果类型来把action序列化成json.如果使用了json拦截器,action将可通过请求中的json内容组装出来,该拦截器需要遵循以下几条规则:
<!-- Result fragment --> <result type="json"> <param name="excludeProperties"> login.password, studentList.*\.sin </param> </result> <!-- Interceptor fragment --> <interceptor-ref name="json"> <param name="enableSMD">true</param> <param name="excludeProperties"> login.password, studentList.*\.sin </param> </interceptor-ref>?
<result type="json"> <param name="includeProperties"> ^entries\[\d+\]\.clientNumber, ^entries\[\d+\]\.scheduleNumber, ^entries\[\d+\]\.createUserId </param> </result>
<result type="json"> <param name="root"> person.job </param> </result>
import java.util.HashMap; import java.util.Map; import com.opensymphony.xwork2.Action; public class JSONExample { private String field1 = "str"; private int[] ints = {10, 20}; private Map map = new HashMap(); private String customName = "custom"; //'transient' fields are not serialized private transient String field2; //fields without getter method are not serialized private String field3; public String execute() { map.put("John", "Galt"); return Action.SUCCESS; } public String getField1() { return field1; } public void setField1(String field1) { this.field1 = field1; } public int[] getInts() { return ints; } public void setInts(int[] ints) { this.ints = ints; } public Map getMap() { return map; } public void setMap(Map map) { this.map = map; } @JSON(name="newName") public String getCustomName() { return this.customName; } }
<?xml version="1.0" encoding="UTF-8" ?> <!DOCTYPE struts PUBLIC "-//Apache Software Foundation//DTD Struts Configuration 2.0//EN" "http://struts.apache.org/dtds/struts-2.0.dtd"> <struts> <package name="example" extends="json-default"> <action name="JSONExample"> <result type="json"/> </action> </package> </struts>?<