JavaScript获取XML资料的数据
日期：2014-05-16 浏览次数：20369 次
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<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>JavaScript获取RSS订阅XML文件的数据</title>
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<style type="text/css">
.zxx_xml_list{margin:30px; padding-left:25px;}
.zxx_xml_list li{list-style-type:disc; padding:3px 0;}
.zxx_xml_list li span{font-size:10px; color:#666666; margin-left:5px;}
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<div class="zxx_out_box">
??? <div class="zxx_in_box">
????????
??????? <h1 class="zxx_title">JavaScript获取RSS订阅XML文件的数据</h1>
??????? <div class="zxx_main_con">
???<ul class="zxx_xml_list" id="xmlBox">
??????????? ?
??????????? </ul>
???<script type="text/javascript">
????var html = "";
????var xml;
????//var url = "http://www.infzm.com/rss/home/rss2.0.xml";
????var url = "../xml/rss2.0.xml";
????if(window.XMLHttpRequest){
?????var xhr = new XMLHttpRequest();
?????xhr.open("GET",url,false);
?????xhr.send(null);
?????xml = xhr.responseXML.documentElement;
????}else if(window.ActiveXObject){
?????xml = new ActiveXObject("Msxml2.DOMDocument");
?????xml.async = false;
?????xml.load(url);
????}else{
?????xml = "";
?????alert("没有获取到xml数据");
????}
????//显示数据
????var items = xml.getElementsByTagName("item");
????if(items.length > 10){
?????for(var i=0; i<10; i+=1){
??????html += '<li><a href="'+items.item(i).getElementsByTagName("link")[0].childNodes[0].nodeValue+'">'+items.item(i).getElementsByTagName("title")[0].childNodes[0].nodeValue+'</a><span>'+items.item(i).getElementsByTagName("pubDate")[0].childNodes[0].nodeValue+'</span></li>';?
?????}
????}else{
?????for(var i=0; i<items.length; i+=1){
??????html += '<li><a href="'+items.item(i).getElementsByTagName("link")[0].childNodes[0].nodeValue+'">'+items.item(i).getElementsByTagName("title")[0].childNodes[0].nodeValue+'</a><span>'+items.item(i).getElementsByTagName("pubDate")[0].childNodes[0].nodeValue+'</span></li>';?
?????}
????}
????document.getElementById("xmlBox").innerHTML = html;?
???</script>
??????? </div>
?????
??? </div>
</div>
</body>
</html>
