ExtJs 树形菜单 Tab标签页容器展现内容
项目中用到了树形菜单,但看代码后,发现有些属性怪怪的,有和没有,页面显示的结果是一样的,为了搞清楚如果弄树形菜单,Ricki自己依样画葫芦,仿造了一个,过程中确实学到不少,所以说,看还不如动手更能掌握,代码如下:
Ext.onReady(function(){
Ext.QuickTips.init();
var tabPanel = new Ext.TabPanel({
region: 'center'
});
var menuTree = new Ext.tree.TreePanel({
useArrows:true,
region: 'west',//指定布局
animate:true,
collapsible: true,
rootVisible:false,//不显示根节点
width:200,
root:new Ext.tree.AsyncTreeNode({//用Ext.tree.TreeNode不行
id:'menuRoot',
text:'menuRoot'
}),
dataUrl:'/MenuAction!loadTree.action',
listeners:{
'click':function(node,e){
var randomnumber=Math.floor(Math.random()*100000);//作为地址的传递参数 以使每次访问时重新获取数据 而非缓存中信息
var tab = Ext.get('tab_'+node.id);
e.stopEvent();//停止事件传递 否则会促使浏览器发送URL(菜单链接)向服务器发送请求
if(node.leaf){
if(tab == null){
alert(node.attributes.href);
var subTabPanel = new Ext.Panel({
id:'tab_'+node.id,
title:node.text,
closable:true,
html:'<iframe id="iframe_'+node.id+'" name="iframe_'+node.id+'" scrolling="auto" frameborder="0" width="100%" height="100%" src="'+node.attributes.href+"?random="+randomnumber+'"></iframe>'
});
tabPanel.add(subTabPanel);//添加该panel
tabPanel.setActiveTab('tab_'+node.id);//激活它
}else{
tabPanel.setActiveTab("tab_"+node.id);//如果已经存在 则激活它
}
}
}
}
});
var viewPort = new Ext.Viewport({
layout:'border',
items:[menuTree,tabPanel]//放进去才开始加载菜单项
});
});
PS:需要注意的问题
1.必须在TreePanel中设置root,否则将报'this.root'为空或不是对象
2.如果在TreePanel中设置region的值,那么Viewport的layout须为border。如:
region : String
Note: this config is only used when this BoxComponent is rendered by a Container which has been configured to use the BorderLayout layout manager (e.g. specifying layout:'border').
3.只设置TreePanel的region的值还不够,还必须设置TabPanel的region值,否则将报:
uncaught exception: No center region defined in BorderLayout ext-comp-1004
4.A TreeLoader provides for lazy loading of an Ext.tree.TreeNode's child nodes from a specified URL. The response must be a JavaScript Array definition whose elements are node definition objects.e.g.:
[{
id: 1,
text: 'A leaf Node',
leaf: true
},{
id: 2,
text: 'A folder Node',
children: [{
id: 3,
text: 'A child Node',
leaf: true
}]
}]
根据这个,只需在server端返回一个节点数组即可。
其中每个节点差不多如下定义:
public class Note{
private int id;
private String text;
private String href;
private boolean leaf;//true if this node is a leaf and does not have children
private ArrayList<Note> Notes;//存放子菜单
......
}
5.当rootVisible为true时,则根节点将显示(这个看自己的情况而定)
6.如果想实现有复选框的树形菜单,那么只需在上面的Note对象中添加boolean checked属性即可。
有空的话,欢迎到红番薯逛逛