function chineseNumber(num)
{
if (isNaN(num) || num > Math.pow(10, 12)) return ""
var cn = "零壹贰叁肆伍陆柒捌玖"
var unit = new Array("拾百千", "分角")
var unit1= new Array("万亿", "")
var numArray = num.toString().split(".")
var start = new Array(numArray[0].length-1, 2)

function toChinese(num, index)
{
var num = num.replace(/\d/g, function ($1)
{
return cn.charAt($1)+unit[index].charAt(start--%4 ? start%4 : -1)
})
return num
}

for (var i=0; i<numArray.length; i++)
{
var tmp = ""
for (var j=0; j*4<numArray[i].length; j++)
{
var strIndex = numArray[i].length-(j+1)*4
var str = numArray[i].substring(strIndex, strIndex+4)
var start = i ? 2 : str.length-1
var tmp1 = toChinese(str, i)
tmp1 = tmp1.replace(/(零.)+/g, "零").replace(/零+$/, "")
tmp1 = tmp1.replace(/^壹拾/, "拾")
tmp = (tmp1+unit1[i].charAt(j-1)) + tmp
}
numArray[i] = tmp
}

numArray[1] = numArray[1] ? numArray[1] : ""
numArray[0] = numArray[0] ? numArray[0]+"元" : numArray[0], numArray[1]
numArray[1] = numArray[1].match(/分/) ? numArray[1] : numArray[1]+"整"
return (numArray[0]+numArray[1]).replace(/^零/, "")
}

<script language="javascript">
function chineseNumber(num)
{
if (isNaN(num) || num > Math.pow(10, 12)) return ""
var cn = "零壹贰叁肆伍陆柒捌玖"
var unit = new Array("拾百千", "分角")
var unit1= new Array("万亿", "")
var numArray = num.toString().split(".")
var start = new Array(numArray[0].length-1, 2)

function toChinese(num, index)
{
var num = num.replace(/\d/g, function ($1)
{
return cn.charAt($1)+unit[index].charAt(start--%4 ? start%4 : -1)
})
return num
}

for (var i=0; i<numArray.length; i++)
{
var tmp = ""
for (var j=0; j*4<numArray[i].length; j++)
{
var strIndex = numArray[i].length-(j+1)*4
var str = numArray[i].substring(strIndex, strIndex+4)
var start = i ? 2 : str.length-1
var tmp1 = toChinese(str, i)
tmp1 = tmp1.replace(/(零.)+/g, "零").replace(/零+$/, "")
//tmp1 = tmp1.replace(/^壹拾/, "拾")
tmp = (tmp1+unit1[i].charAt(j-1)) + tmp
}
numArray[i] = tmp
}

numArray[1] = numArray[1] ? numArray[1] : ""
numArray[0] = numArray[0] ? numArray[0]+"元" : numArray[0], numArray[1]
numArray[1] = numArray[1].match(/分/) ? numArray[1] : numArray[1]+"整"
return (numArray[0]+numArray[1]).replace(/^零/, "")
}
alert(chineseNumber(1111111111))
</script>

------解决方案--------------------

探讨

如：100000.01，结果必须为:壹拾万零一分
1000000000.01，结果必须为:壹拾亿零一分

注：二十万或者二十亿这些不用修改


代码如下，请标明修改的地方，谢谢！

JScript code



function chineseNumber(num)
{
if (isNaN(num) || num > Math.pow(10, 12)) return ""
va……


------解决方案--------------------

我自己写一个给你，看看符合你要求不？
JScript code

function chineseNumber(num)
{
    if (isNaN(num) || num > Math.pow(10, 12)) return "";
    var CharBig = new Array("零","壹","贰","叁","肆","伍","陆","柒","捌","玖");
    var CharBig2 = new Array("元","拾","佰","仟","万","拾","佰","仟","亿",&quo