日期:2014-05-16  浏览次数:20449 次

Android JSON解析示例代码
来自Google官方的有关Android平台的JSON解析示例,如果远程服务器使用了json而不是xml的数据提供,在Android平台上已经内置的org.json包可以很方便的实现手机客户端的解析处理。下面Android123一起分析下这个例子,帮助Android开发者需要有关 HTTP通讯、正则表达式、JSON解析、appWidget开发的一些知识。

public class WordWidget extends AppWidgetProvider { //appWidget
    @Override
    public void onUpdate(Context context, AppWidgetManager appWidgetManager,
            int[] appWidgetIds) {

        context.startService(new Intent(context, UpdateService.class)); //避免ANR,所以Widget中开了个服务
    }

    public static class UpdateService extends Service {
        @Override
        public void onStart(Intent intent, int startId) {
            // Build the widget update for today
            RemoteViews updateViews = buildUpdate(this);

            ComponentName thisWidget = new ComponentName(this, WordWidget.class);
            AppWidgetManager manager = AppWidgetManager.getInstance(this);
            manager.updateAppWidget(thisWidget, updateViews);
        }


        public RemoteViews buildUpdate(Context context) {
            // Pick out month names from resources
            Resources res = context.getResources();
            String[] monthNames = res.getStringArray(R.array.month_names);

             Time today = new Time();
            today.setToNow();


            String pageName = res.getString(R.string.template_wotd_title,
                    monthNames[today.month], today.monthDay);
            RemoteViews updateViews = null;
            String pageContent = "";

            try {

                SimpleWikiHelper.prepareUserAgent(context);
                pageContent = SimpleWikiHelper.getPageContent(pageName, false);
            } catch (ApiException e) {
                Log.e("WordWidget", "Couldn't contact API", e);
            } catch (ParseException e) {
                Log.e("WordWidget", "Couldn't parse API response", e);
            }


            Pattern pattern = Pattern.compile(SimpleWikiHelper.WORD_OF_DAY_REGEX); //正则表达式处理,有关定义见下面的SimpleWikiHelper类
            Matc