日期:2014-05-16  浏览次数:20324 次

js问题,为什么获取不了id元素??求解
PicList.prototype.run = function(){ log(this.elem) //null } 这句获取了空值...哪里出错了?
JScript code
function log(i){ return console.log(i); } 

    function $ (id)
    {
        if(typeof id === "string"){
            return document.getElementById(id);
        }else{
            return id;
        }
    }
    function PicList(){
        this.elem = $(arguments[0]);
        this.arr = [];
        var iTarget = [
            { left:0 },
            { left:50 },
            { left:100 },
            { left:150 },
            { left:200 }
        ];
        
        this.run();
    }
    PicList.prototype.run = function(){
        log(this.elem)  //null
    }
    Animate.prototype = new PicList("wrap");
    function Animate(){
        log(this.arr)
    }
    var obj = new Animate();
//HTML
<div id="wrap">    </div>


------解决方案--------------------
<script type="text/javascript">
function log(i){ return console.log(i); } 

function $ (id)
{
if(typeof id === "string"){
return document.getElementById(id);
}else{
return id;
}
}
function PicList(){
this.elem = $(arguments[0]);
alert(this.elem.id);
this.arr = [];
var iTarget = [
{ left:0 },
{ left:50 },
{ left:100 },
{ left:150 },
{ left:200 }
];

this.run();
}
PicList.prototype.run = function(){
log(this.elem) //null
}
</script>

</head>

<body>
<div id="wrap"> </div>
<script type="text/javascript">
Animate.prototype = new PicList("wrap");
function Animate(){
log(this.arr)
}
var obj = new Animate();
</script>
这样试试 貌似是因为Animate.prototype = new PicList("wrap");时你的那个div还没加载进来,所以为null
我也是猜的 js继承那块没好好看