js中怎么实现二维数组的转置。
日期：2014-05-16 浏览次数：20538 次
js中如何实现二维数组的转置。。。
如下代码为什么不能实现二维数组的转置？？
<html>
<body>
<script language="javascript">
var a=[[5,4,5,4,5,5,1],['fd',45,3.6,7,22,56,7],[4,2,5,'gshshgjh',45,525,2]];
var b=[];
for(var i=0;i<a.length;i++){
for(var j=0;j<a[i].length;j++){
b[j][i]=a[i][j];
}
}
for(var i=0;i<a.length;i++){
for(var j=0;j<a[i].length;j++){
document.writeln(j[i][j]);
}
document.writeln("<br/>");
}
</script>
</body>
</html>
------解决方案--------------------
<html>
<body>
<script language="javascript">
var a = [[5, 4, 5, 4, 5, 5, 1], ['fd', 45, 3.6, 7, 22, 56, 7], [4, 2, 5, 'gshshgjh', 45, 525, 2]];
var b = [];
for (var i = 0; i < a.length; i++) {
b[i] = [];
for (var j = 0; j < a[i].length; j++) {
b[i][j] = a[i][j];
}
}
for (var i = 0; i < a.length; i++) {
for (var j = 0; j < a[i].length; j++) {
document.writeln(b[i][j]);
}
document.writeln("<br/>");
}
</script>
</body>
</html>
------解决方案--------------------
<html>
<body>
<script language="javascript">
var a=[[5,4,5,4,5,5,1],['fd',45,3.6,7,22,56,7],[4,2,5,'gshshgjh',45,525,2]];
var b=[];
for(var i=0;i<a.length;i++){
b[i] = [];
for(var j=0;j<a[i].length;j++){
b[i][j] = a[i][j];
}
}
for(var i=0;i<a.length;i++){
for(var j=0;j<a[i].length;j++){
document.writeln(b[i][j]);
}
document.writeln("<br/>");
}
</script>
</body>
</html>
这个意思？
------解决方案--------------------
------解决方案--------------------
------解决方案--------------------
我想我明白你意思了，是不是下面这样的？
<html>
<body>
<script language="javascript">
var a = [[5, 4, 5, 4, 5, 5, 1], ['fd', 45, 3.6, 7, 22, 56, 7], [4, 2, 5, 'gshshgjh', 45, 525, 2]];
var b = [];
for (var j = 0; j < a[0].length; j++) {
b[j] = [];
for (var i = 0; i < a.length; i++) {
b[j][i] = a[i][j];
}
}
for (var i = 0; i < b.length; i++) {
for (var j = 0; j < b[i].length; j++) {
document.writeln(b[i][j]);
}
document.writeln("<br/>");
}
</script>
</body>
</html>
如下代码为什么不能实现二维数组的转置？？
<html>
<body>
<script language="javascript">
var a=[[5,4,5,4,5,5,1],['fd',45,3.6,7,22,56,7],[4,2,5,'gshshgjh',45,525,2]];
var b=[];
for(var i=0;i<a.length;i++){
for(var j=0;j<a[i].length;j++){
b[j][i]=a[i][j];
}
}
for(var i=0;i<a.length;i++){
for(var j=0;j<a[i].length;j++){
document.writeln(j[i][j]);
}
document.writeln("<br/>");
}
</script>
</body>
</html>
------解决方案--------------------
<html>
<body>
<script language="javascript">
var a = [[5, 4, 5, 4, 5, 5, 1], ['fd', 45, 3.6, 7, 22, 56, 7], [4, 2, 5, 'gshshgjh', 45, 525, 2]];
var b = [];
for (var i = 0; i < a.length; i++) {
b[i] = [];
for (var j = 0; j < a[i].length; j++) {
b[i][j] = a[i][j];
}
}
for (var i = 0; i < a.length; i++) {
for (var j = 0; j < a[i].length; j++) {
document.writeln(b[i][j]);
}
document.writeln("<br/>");
}
</script>
</body>
</html>
------解决方案--------------------
<html>
<body>
<script language="javascript">
var a=[[5,4,5,4,5,5,1],['fd',45,3.6,7,22,56,7],[4,2,5,'gshshgjh',45,525,2]];
var b=[];
for(var i=0;i<a.length;i++){
b[i] = [];
for(var j=0;j<a[i].length;j++){
b[i][j] = a[i][j];
}
}
for(var i=0;i<a.length;i++){
for(var j=0;j<a[i].length;j++){
document.writeln(b[i][j]);
}
document.writeln("<br/>");
}
</script>
</body>
</html>
这个意思？
------解决方案--------------------
------解决方案--------------------
------解决方案--------------------
我想我明白你意思了，是不是下面这样的？
<html>
<body>
<script language="javascript">
var a = [[5, 4, 5, 4, 5, 5, 1], ['fd', 45, 3.6, 7, 22, 56, 7], [4, 2, 5, 'gshshgjh', 45, 525, 2]];
var b = [];
for (var j = 0; j < a[0].length; j++) {
b[j] = [];
for (var i = 0; i < a.length; i++) {
b[j][i] = a[i][j];
}
}
for (var i = 0; i < b.length; i++) {
for (var j = 0; j < b[i].length; j++) {
document.writeln(b[i][j]);
}
document.writeln("<br/>");
}
</script>
</body>
</html>
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