求解，getjson函数哪里写错了啊
<script src="jquery-1.7.2.min.js" type="text/javascript"></script>
<script>
$(function(){
$.getjson("http://rate.taobao.com/member_rate.htm?content=1&result=0&from=rate&user_id=281461646&identity=1&rater=0&direction=0&timeLine=-7&callback=shop_rate_list", function(json){
  alert("JSON Data: " + json);
});
})

弹不出获取的代码，求哪里写错了

------解决方案--------------------

JScript code

$(function(){
$.getJSON("http://rate.taobao.com/member_rate.htm?content=1&result=0&from=rate&user_id=281461646&identity=1&rater=0&direction=0&timeLine=-7&callback=?", 
   function(json){
      alert("JSON Data: " + json);
    });
})