日期:2014-05-16 浏览次数:20306 次
var j ={"0":["75","test4","test41","ddd"],"1":["76","test5","test51","ddd"]} var arr= []; $.each(j,function(i,o){ arr.push(o[2]) }) alert(arr)
------解决方案--------------------
var json = { "0": ["75", "test4", "test41", "ddd"], "1": ["76", "test5", "test51", "ddd"] }; for(k in json ){ alert(json[k][2]); }