求年月的正则表达式yyyy-MM
javascript脚本验证正则表达式
我有一个年月日的正则表达式想换成判断年月的正则表达式
年月日判断的如下　　这个好使
case   "yyyy-mm-dd "   :
//m   =   op.match(new   RegExp( "^\\s*((\\d{4})|(\\d{2}))([-./])(\\d{1,2})\\4(\\d{1,2})\\s*$ "));
m   =   op.match(new   RegExp( "^\\s*((\\d{4})|(\\d{2}))([-])(\\d{2})\\4(\\d{2})\\s*$ "));
if(m   ==   null   )   return   false;
day   =   m[6];
month   =   m[5];
year   =     (m[2].length   ==   4)   ?   m[2]   :   GetFullYear(parseInt(m[3],   10));
newdate   =   year+ '/ '+month+ '/ '+day;
date   =   new   Date(newdate);
  return   (typeof(date)   ==   "object "   &&   year   ==   date.getFullYear()   &&   (month-1)   ==   date.getMonth()   &&   day   ==   date.getDate());
break;

------解决方案--------------------
function checkDate(objdate)
{
var re=/\d{4}\/\d{2}\//;
var re1 = /\d{4}\d{2}/;
if(re.test(objdate) || re1.test(objdate))
{
return true;
}
return false;
}
------解决方案--------------------
String.prototype.isDate = function()
{
var r = this.match(/^(\d{1,4})(-)(\d{1,2})$/);
if(r==null)return false; var d = new Date(r[1], r[3]-1, '1 ');
return (d.getFullYear()==r[1]&&(d.getMonth()+1)==r[3]&&d.getDate()== '1 ');
}
alert( "2002-1 ".isDate());
alert( "2002-16 ".isDate());