怎么输出成HTML代码...
我想输出成这样..
<SCRIPT>
var   widths=384;
var   heights=265;
var   counts=4;

img1=new   Image();img1.src= '/imagelist/07/07/4219635_8980.jpg ';

img2=new   Image();img2.src= '/imagelist/07/07/4218572_9143.jpg ';

img3=new   Image();img3.src= '/imagelist/07/07/4218055_8472.jpg ';

img4=new   Image();img4.src= '/imagelist/07/07/4217763_5661.jpg ';

url1=new   Image();url1.src= 'http://pic.yesky.com/pic/tuijian/ ';

url2=new   Image();url2.src= 'http://pic.yesky.com/pic/tuijian/ ';

url3=new   Image();url3.src= 'http://pic.yesky.com/pic/tuijian/ ';

url4=new   Image();url4.src= 'http://pic.yesky.com/pic/tuijian/ ';
</SCRIPT>

查看源代码的时候就是上边那样....
但我这样写:
<SCRIPT>
var   widths=313;
var   heights=231;
var   counts=5;

for(i=1;i <=5;i++){    
    document.write( "img[ "   +   i   +   "]=new   Image();img[ "   +   i   +   "].src= '8888.gif '; ");
    document.write( "url[ "   +   i   +   "]=new   Image();url[ "   +   i   +   "].src= 'www.wwww.com '; ");
   
}

</SCRIPT>
就直接输出到页面了   ...
请问怎么能实现???

------解决方案--------------------
不能输出
只能用eval()函数

eval( "img[ " + i + "]=new Image();img[ " + i + "].src= '8888.gif '; ");
eval( "url[ " + i + "]=new Image();url[ " + i + "].src= 'www.wwww.com '; ");

eval能直接执行指定的JS代码