调用form.submit()方法不同,而结果也不同?该怎么解决
日期：2014-05-16 浏览次数：20476 次
调用form.submit()方法不同,而结果也不同?
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.0 Transitional//EN ">
<HTML>
<HEAD>
<TITLE> New Document </TITLE>
<META NAME= "Generator " CONTENT= "EditPlus ">
<META NAME= "Author " CONTENT= " ">
<META NAME= "Keywords " CONTENT= " ">
<META NAME= "Description " CONTENT= " ">
</HEAD> <SCRIPT LANGUAGE= "JavaScript ">
<!--
function cc()
{
alert( "cc ");
document.forms[0].submit();
}
function check()
{
alert( "false ");
return false;
}
//-->
</SCRIPT>
<BODY>
<form name= "form1 " id= "form1 " onsubmit= "return check(); ">
<input type= "button " onclick= "cc() " value= "submit "/>
<input type= "submit " value= "submit ">
</form>
</BODY>
</HTML>
为何第一个submit不触发onsubmit事件呢?
------解决方案--------------------
改成这样就好了：
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.0 Transitional//EN ">
<HTML>
<HEAD>
<TITLE> New Document </TITLE>
<META NAME= "Generator " CONTENT= "EditPlus ">
<META NAME= "Author " CONTENT= " ">
<META NAME= "Keywords " CONTENT= " ">
<META NAME= "Description " CONTENT= " ">
</HEAD> <SCRIPT LANGUAGE= "JavaScript ">
<!--
function cc()
{
alert( "cc ");
//document.forms[0].submit();
document.getElementById( "btnSubmit ").click();
}
function check()
{
alert( "false ");
return false;
}
//-->
</SCRIPT>
<BODY>
<form name= "form1 " id= "form1 " onsubmit= "return check(); ">
<input type= "button " onclick= "cc() " value= "submit "/>
<input type= "submit " value= "submit " id= "btnSubmit ">
</form>
</BODY>
</HTML>
我在做一些类似的问题时也遇到过跟你一样的问题，原因不得而知，一般都是通过对一个type为submit的按钮的click事件来实现对表单的提交。
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.0 Transitional//EN ">
<HTML>
<HEAD>
<TITLE> New Document </TITLE>
<META NAME= "Generator " CONTENT= "EditPlus ">
<META NAME= "Author " CONTENT= " ">
<META NAME= "Keywords " CONTENT= " ">
<META NAME= "Description " CONTENT= " ">
</HEAD> <SCRIPT LANGUAGE= "JavaScript ">
<!--
function cc()
{
alert( "cc ");
document.forms[0].submit();
}
function check()
{
alert( "false ");
return false;
}
//-->
</SCRIPT>
<BODY>
<form name= "form1 " id= "form1 " onsubmit= "return check(); ">
<input type= "button " onclick= "cc() " value= "submit "/>
<input type= "submit " value= "submit ">
</form>
</BODY>
</HTML>
为何第一个submit不触发onsubmit事件呢?
------解决方案--------------------
改成这样就好了：
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.0 Transitional//EN ">
<HTML>
<HEAD>
<TITLE> New Document </TITLE>
<META NAME= "Generator " CONTENT= "EditPlus ">
<META NAME= "Author " CONTENT= " ">
<META NAME= "Keywords " CONTENT= " ">
<META NAME= "Description " CONTENT= " ">
</HEAD> <SCRIPT LANGUAGE= "JavaScript ">
<!--
function cc()
{
alert( "cc ");
//document.forms[0].submit();
document.getElementById( "btnSubmit ").click();
}
function check()
{
alert( "false ");
return false;
}
//-->
</SCRIPT>
<BODY>
<form name= "form1 " id= "form1 " onsubmit= "return check(); ">
<input type= "button " onclick= "cc() " value= "submit "/>
<input type= "submit " value= "submit " id= "btnSubmit ">
</form>
</BODY>
</HTML>
我在做一些类似的问题时也遇到过跟你一样的问题，原因不得而知，一般都是通过对一个type为submit的按钮的click事件来实现对表单的提交。
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