输入生日即可计算出下个生日的天数及存活天数-JS特效-爱易网页

输入生日即可计算出下个生日的天数及存活天数

日期：2014-05-18　浏览次数：20151 次

欢迎光临爱易网网页脚本特效中心，点击运行按钮演示特效：

以下是程序代码

有什么问题请到<a href='/bbs/index.asp?boardid=2'>论坛</a>中发表<br>


<!--要完成此效果需要三个步骤

第一步：把如下代码加入到<head>区域中-->

<SCRIPT LANGUAGE="JavaScript">
<!-- Begin
var byear = prompt('请输入你的出生年份','1976');
var mm = prompt('请输入你的出生月份','6');
var bday = prompt('请输入你的出生日','10');

var year = new Date();
var year2 = year.getYear();
var year3 = (year < 2000) ? year2 + 1900 : year2;
thedate = new Date();
mm2 = thedate.getMonth() + 1;
dd2 = thedate.getDate();
yy2 = thedate.getYear();
if (yy2 < 100) yy2 += 1900
yourage = yy2 - byear;
if (mm2 < mm) yourage--;
if ((mm2 == mm) && (dd2 < bday)) yourage--;
TMonth = new Array(
'January','February','March',
'April','May','June','July',
'August','September','October',
'November','December'
);
CurMonth = mm - 1;
bmonth = TMonth[CurMonth];
var age2 = yourage + 1;
var timerID;
var timerRunning = false;
var today = new Date();
var startday = new Date();
var enday = new Date();
var secPerDay = 0;
var minPerDay = 0;
var hourPerDay = 0;
var secsLeft = 0;
var secsRound = 0;
var secsRemain = 0;
var minLeft = 0;
var minRound = 0;
var minRemain = 0;
var timeRemain = 0;
function stopclock() {
if(timerRunning)
clearTimeout(timerID);
timerRunning = false;
}
function startclock() {
stopclock();
showtime();
showtime1();
}
function showtime() {
today = new Date();
enday = new Date(""+bmonth+", "+bday+" "+year3+" 00:00");
enday.setYear(""+year3+"");
secsPerDay = 1000 ;
minPerDay = 60 * 1000 ;
hoursPerDay = 60 * 60 * 1000;
PerDay = 24 * 60 * 60 * 1000;
secsLeft = (enday.getTime() - today.getTime()) / minPerDay;
secsRound = Math.round(secsLeft);
secsRemain = secsLeft - secsRound;
secsRemain = (secsRemain < 0) ? secsRemain = 60 - ((secsRound - secsLeft) * 60) : secsRemain =

(secsLeft - secsRound) * 60;
secsRemain = Math.round(secsRemain);
minLeft = ((enday.getTime() - today.getTime()) / hoursPerDay);
minRound = Math.round(minLeft);
minRemain = minLeft - minRound;
minRemain = (minRemain < 0) ? minRemain = 60 - ((minRound - minLeft)  * 60) : minRemain =

((minLeft - minRound) * 60);
minRemain = Math.round(minRemain - 0.495);
hoursLeft = ((enday.getTime() - today.getTime()) / PerDay);
hoursRound = Math.round(hoursLeft);
hoursRemain = hoursLeft - hoursRound;
hoursRemain = (hoursRemain < 0) ? hoursRemain = 24 - ((hoursRound - hoursLeft)  * 24) :

hoursRemain = ((hoursLeft - hoursRound) * 24);
hoursRemain = Math.round(hoursRemain - 0.5);
daysLeft = ((enday.getTime() - today.getTime()) / PerDay);
daysLeft = (daysLeft - 0.5);
daysRound = Math.round(daysLeft);
daysRemain = daysRound;
if (daysRemain == 1) day_rem = " 天, "
else day_rem = " 天, "
if (hoursRemain == 1) hour_rem = " 小时, "
else hour_rem = " 小时, "
if (minRemain == 1) min_rem = " 分钟, "
else min_rem = " 分钟, "
if (secsRemain == 1) sec_rem = " 秒"
else sec_rem = " 秒"
timeRemain = daysRemain + day_rem + hoursRemain + hour_rem + minRemain + min_rem + secsRemain +

sec_rem;
document.down.face.value = timeRemain;
timerID = setTimeout("showtime()",1000);
timerRunning = true;
if (daysRemain < 0) year3 = year3 + 1
}
function showtime1() {
startday = new Date(""+bmonth+" "+bday+", "+byear+" 00:00 EDT");
startday.setYear(""+byear+"");
today = new Date();
secsPerDay = 1000 ;
minPerDay = 60 * 1000 ;
hoursPerDay = 60 * 60 * 1000;
PerDay = 24 * 60 * 60 * 1000;
secsLeft = (today.getTime() - startday.getTime()) / minPerDay;
secsRound = Math.round(secsLeft);
secsRemain = secsLeft - secsRound;
secsRemain = (secsRemain < 0) ? secsRemain = 60 - ((secsRound - secsLeft) * 60) : secsRemain =

(secsLeft - secsRound) * 60;
secsRemain = Math.round(secsRemain);
minLeft = ((today.getTime() - startday.g</div></div>

<div class="clearfix"></div>
                    </div>
                    <nav aria-label="...">
                        <ul class="pager">
                            <li class="previous"><a href="4667">上一篇：狡猾的按钮特效</a></li>

<li class="next"><a href="1001">下一篇：文本框内显示时间的脚本</a></li>
                        </ul>
                    </nav>

<div class="alert alert-warning" role="alert">
                        <strong>免责声明：</strong> 本文仅代表作者个人观点，与爱易网无关。其原创性以及文中陈述文字和内容未经本站证实，对本文以及其中全部或者部分内容、文字的真实性、完整性、及时性本站不作任何保证或承诺，请读者仅作参考，并请自行核实相关内容。
                    </div>

<div class="col-md-6 col-xs-12">
                      <li class="articleAbout"><a href='/ItNews/34352' title='纸媒深探版权蓝海抗衡互联网的时机到来了' target="_blank">
                        纸媒深探版权蓝海抗衡互联网的时机到来了</a></li></div>
                   
                
                  <div class="col-md-6 col-xs-12">
                      <li class="articleAbout"><a href='/ItNews/34327' title='打车软件“明补变暗补”背后的小算盘' target="_blank">
                        打车软件“明补变暗补”背后的小算盘</a></li></div>
                   
                
                  <div class="col-md-6 col-xs-12">
                      <li class="articleAbout"><a href='/ItNews/34294' title='频繁自杀 折射媒体变革中的媒体人迷茫与压力并存' target="_blank">
                        频繁自杀 折射媒体变革中的媒体人迷茫与压力并存</a></li></div>
                   
                
                  <div class="col-md-6 col-xs-12">
                      <li class="articleAbout"><a href='/ItNews/34166' title='苹果多色彩！葫芦里究竟卖的什么药' target="_blank">
                        苹果多色彩！葫芦里究竟卖的什么药</a></li></div>
                   
                
                  <div class="col-md-6 col-xs-12">
                      <li class="articleAbout"><a href='/ItNews/10815' title='中移动业绩增长趋缓 目光转向海外市场' target="_blank">
                        中移动业绩增长趋缓 目光转向海外市场</a></li></div>
                   
                
                  <div class="col-md-6 col-xs-12">
                      <li class="articleAbout"><a href='/ItNews/34133' title='人们为什么总愿尝试新社交网络？' target="_blank">
                        人们为什么总愿尝试新社交网络？</a></li></div>
                   
                
                  <div class="col-md-6 col-xs-12">
                      <li class="articleAbout"><a href='/ItNews/34324' title='Line风靡亚洲，在北美却进展缓慢' target="_blank">
                        Line风靡亚洲，在北美却进展缓慢</a></li></div>
                   
                
                  <div class="col-md-6 col-xs-12">
                      <li class="articleAbout"><a href='/ItNews/34454' title='永不磨灭的九大尖端编程语言' target="_blank">
                        永不磨灭的九大尖端编程语言</a></li></div>
                   
                
                  <div class="col-md-6 col-xs-12">
                      <li class="articleAbout"><a href='/ItNews/34293' title='携程整合去哪儿陷入僵局 欲联手老对手艺龙' target="_blank">
                        携程整合去哪儿陷入僵局 欲联手老对手艺龙</a></li></div>
                   
                
        </ol>
    </div>
</div>

</div>

</div>
            </div>
            <div class="clearfix"></div>

<footer class=" footer navbar-bottom">
<em>友情链接：</em>
    
      <a href="http://www.aiyiweb.com/" target="_blank">爱易网 </a>            
    
      <a href="http://www.aiyiweb.com/" target="_blank">云虚拟主机技术 </a>            
    
      <a href="http://www.aiyiweb.com/" target="_blank">云服务器技术 </a>            
    
      <a href="http://www.aiyiweb.com/" target="_blank">程序设计技术 </a>            
    
      <a href="http://www.aiyiweb.com/" target="_blank">开发网站 </a>            
    
      <a href="http://www.aiyiweb.com/" target="_blank">APP开发教程 </a>            
    
<br />
<script type="text/javascript">(function(){document.write(unescape('%3Cdiv id="bdcs"%3E%3C/div%3E'));var bdcs = document.createElement('script');bdcs.type = 'text/javascript';bdcs.async = true;bdcs.src = 'http://znsv.baidu.com/customer_search/api/js?sid=15239353030108964139' + '&plate_url=' + encodeURIComponent(window.location.href) + '&t=' + Math.ceil(new Date()/3600000);var s = document.getElementsByTagName('script')[0];s.parentNode.insertBefore(bdcs, s);})();</script>

Copyright © 2013-2025 爱易网页 当前在线：259人　
        网站在2时2分5秒内访问总人数：27049人
    当前 4.44%
　<a href="https://beian.miit.gov.cn" target="_blank">粤ICP备18100884号-2 </a>
<script charset="UTF-8" id="LA_COLLECT" src="//sdk.51.la/js-sdk-pro.min.js"></script>
<script>LA.init({ id: "JszEmKrtpbU59dY5", ck: "JszEmKrtpbU59dY5" })</script>

</footer>

</div>
   
</body>
</html>