线程清理处理程序
#include "apue.h"
#include <pthread.h>

void
cleanup(void *arg)
{
printf("cleanup: %s\n", (char *)arg);
}

void *
thr_fn1(void *arg)
{
printf("thread 1 start\n");
pthread_cleanup_push(cleanup, "thread 1 first handler");
pthread_cleanup_push(cleanup, "thread 1 second handler");
printf("thread 1 push complete\n");
if (arg)
return((void *)1);
pthread_cleanup_pop(0);
pthread_cleanup_pop(0);
return((void *)1);
}

void *
thr_fn2(void *arg)
{
printf("thread 2 start\n");
pthread_cleanup_push(cleanup, "thread 2 first handler");
pthread_cleanup_push(cleanup, "thread 2 second handler");
printf("thread 2 push complete\n");
if (arg)
pthread_exit((void *)2);
pthread_cleanup_pop(0);
pthread_cleanup_pop(0);
pthread_exit((void *)2);
}

int
main(void)
{
int err;
pthread_t tid1, tid2;
void *tret;

err = pthread_create(&tid1, NULL, thr_fn1, (void *)1);
if (err != 0)
err_quit("can't create thread 1: %s\n", strerror(err));
err = pthread_create(&tid2, NULL, thr_fn2, (void *)1);
if (err != 0)
err_quit("can't create thread 2: %s\n", strerror(err));
err = pthread_join(tid1, &tret);
if (err != 0)
err_quit("can't join with thread 1: %s\n", strerror(err));
printf("thread 1 exit code %d\n", (int)tret);
err = pthread_join(tid2, &tret);
if (err != 0)
err_quit("can't join with thread 2: %s\n", strerror(err));
printf("thread 2 exit code %d\n", (int)tret);
exit(0);
}
我想请问的是：我把pthread_join注释以后，为什么两个线程入口函数中的代码为啥不输出？？？（我的系统是Fedora16）

------解决方案--------------------
因为线程还没来得及跑，你main都退掉了。。。进程都关了。