100分请教高手一个CPU的问题
RELEASE_RET_GPIO
bit [31] RELEASE_RET_GPIO is retention control signal to normal I/O pad.
If you want to disable RELEASE_RET_GPIO, set to 1. After
RELEASE_RET_GPIO becomes OFF, this bit will be cleared to 0.
Usage1: Wakeup from IDLE, DEEP-IDLE, STOP, or DEEP-STOP with top-level
logic ON
-> No need to set this register field.

Usage2: Wakeup from DEEP-IDLE, STOP, or DEEP-STOP with top-level logic OFF.
-> Set HIGH on this register field to that corresponding PAD starts to
work.

Usage3: Wakeup from SLEEP.
-> First restore GPIO configuration options to those values before
entering SLEEP mode. And then set HIGH on this register field to that
corresponding PAD starts to work.
0 = Auto clear
1 = RELEASE_RET_GPIO

三星cpu spec上面的这段话：Usage3中的:
0 = Auto clear
1 = RELEASE_RET_GPIO
是什么意思？
什么情况下RELEASE_RET_GPIO 会becomes OFF？

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具体要根据硬件手册的上下文来分析， 这是配置某个引脚的功能， bit [31]即31位的的功能。
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这个方面不熟悉，只好友情帮顶了，学习下
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我也看不懂，感觉还需要看更多的内容才能明白。
如果没人给你更好的建议，
我建议你把寄存器相应的位分别置为0和1试一试就知道了。
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问题锁定范围已经很小了 bit [31] 入口