这个话语正确吗
日期：2014-05-17 浏览次数：20518 次
这个语句正确吗
insert into k07 (a0188,k0700,k0701)
select * from (select a.a0188,convert(char(10),c.cardtime,23) k0700,convert(char(8),c.cardtime,24) k0701
from a01 a ,hwatt..kqz_employee b,hwatt..kqz_card c
where a.a0190=b.employeecode and b.employeeid=c.employeeid) a
where not exists (select*from k07)
------解决方案--------------------
------解决方案--------------------
insert into k07 (a0188,k0700,k0701)
select * from (select a.a0188,convert(char(10),c.cardtime,23) k0700,convert(char(8),c.cardtime,24) k0701
from a01 a ,hwatt..kqz_employee b,hwatt..kqz_card c
where a.a0190=b.employeecode and b.employeeid=c.employeeid) a
where not exists (select*from k07)
------解决方案--------------------
INSERT INTO k07
( a0188 ,
k0700 ,
k0701
)
SELECT *
FROM ( SELECT a.a0188 ,
CONVERT(CHAR(10), c.cardtime, 23) k0700 ,
CONVERT(CHAR(8), c.cardtime, 24) k0701
FROM a01 a ,
hwatt..kqz_employee b ,
hwatt..kqz_card c
WHERE a.a0190 = b.employeecode
AND b.employeeid = c.employeeid
) a
WHERE NOT EXISTS ( SELECT 1
FROM k07
WHERE a.主键 = k07.主键 )
------解决方案--------------------
insert into k07 (a0188,k0700,k0701)
select
*
from
(select
a.a0188,convert(char(10),c.cardtime,23) k0700,convert(char(8),c.cardtime,24) k0701
from a01 a ,hwatt..kqz_employee b,hwatt..kqz_card c
where a.a0190=b.employeecode and b.employeeid=c.employeeid) a
where
not exists (select*from k07 where a0188=a.a0188 and k0700=a.k0700 and k0701=a.k0701)
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