一条Oracle话语，报错了，求大侠们改下。
日期：2014-05-17 浏览次数：20658 次
一条Oracle语句，报错了，求大侠们改下。。。
SELECT S.NO 学号,
CASE
WHEN S.ID = '1210527501' THEN
(SELECT DATE
FROM STU
WHERE ID = '1210527501') AS 时间1,
WHEN S.ID = '1210527502' THEN
(SELECT DATE
FROM STU
WHERE ID = '1210527502') AS 时间2,
WHEN S.ID = '1210527503' THEN
(SELECT DATE
FROM STU
WHERE ID = '1210527503') AS 时间3,
ELSE
END
FROM STU S
WHERE S.NO LIKE '1240156742010%';
报红色部分缺失关键字。。。
------解决方案--------------------
語法錯誤了吧![]()
你想表達的是這樣吧:
又或者:
SELECT S.NO 学号,
CASE
WHEN S.ID = '1210527501' THEN
(SELECT DATE
FROM STU
WHERE ID = '1210527501') AS 时间1,
WHEN S.ID = '1210527502' THEN
(SELECT DATE
FROM STU
WHERE ID = '1210527502') AS 时间2,
WHEN S.ID = '1210527503' THEN
(SELECT DATE
FROM STU
WHERE ID = '1210527503') AS 时间3,
ELSE
END
FROM STU S
WHERE S.NO LIKE '1240156742010%';
报红色部分缺失关键字。。。
------解决方案--------------------
語法錯誤了吧
你想表達的是這樣吧:
SELECT S.NO 学号,
(SELECT TOP 1 DATE
FROM STU
WHERE ID = S.ID AND S.ID = '1210527501') AS 时间1,
(SELECT TOP 1 DATE
FROM STU
WHERE ID = S.ID AND S.ID = '1210527502') AS 时间2,
(SELECT TOP 1 DATE
FROM STU
WHERE ID = S.ID AND S.ID = '1210527503') AS 时间3
FROM STU S
WHERE S.NO LIKE '1240156742010%';
又或者:
SELECT S.NO 学号,
CASE
WHEN S.ID = '1210527501' THEN
(SELECT TOP 1 DATE
FROM STU
WHERE ID = '1210527501')
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