日期:2014-05-17  浏览次数:20842 次

sql根据日期分组查询
我用sql2005,表(table1)如下

id zhuti riqi
1 大家好 2012-1-3
2 大 2012-1-5
3 家 2012-1-5
4 好 2012-1-10
5 欢迎 2012-1-10
6 光临 2012-1-10

我想要实现的功能是,一段sql语句实现下列输出:

2012-1-10
光临
欢迎

2012-1-5


2012-1-3
大家好

如何实现?请教大家了,谢谢!


------解决方案--------------------
with t1 as (
select max(id) id,riqi from table1 group by riqi
),t2 as (
select id,zhuti from table1 
),t3 as (
select id,riqi as a,1 id2 from t1 
union all 
select id,zhuti,2 id2 from t2 
)
select a from t3 order by id desc,id2
------解决方案--------------------
SQL code
create table tb#
(id int not null,
 zhuti varchar(10),
 riqi datetime)

insert into tb#(id, zhuti ,riqi)
select 1, '大家好','2012-1-3'
union all select 2,'大',' 2012-1-5'
union all select 3 , '家 ','2012-1-5'
union all select 4 , '好 ','2012-1-10'
union all select 5 , '欢迎','2012-1-10'
union all select 6 , '光临 ','2012-1-10'

select * from tb#

select zhuti 
from(
select distinct cast(year(riqi) as varchar(4))+' - '+ cast(month(riqi) as varchar(2))+' - '+ cast(day(riqi) as varchar(2)) as zhuti,riqi from tb#
union all
select zhuti,riqi from tb# ) as a
order by riqi desc,zhuti

--结果
/*
2012 - 1 - 10
光临 
好 
欢迎
2012 - 1 - 5
大
家 
2012 - 1 - 3
大家好
*/