查询求解
create table t_test
(
  t_num varchar(30),
  t_time varchar(30),
  t_other varchar(30)
)
insert into t_test values('1001','20120701','aaaaaaaaaaaa');
insert into t_test values('1001','20120707','bbbbbbbbbbbb');
insert into t_test values('1002','20120702','cccccccccccc');
insert into t_test values('1003','20120706','dddddddddddd');
insert into t_test values('1003','20120709','eeeeeeeeeeee');


如何查询出1001,1002,1003这三个账号的时间最新的信息

------解决方案--------------------

SQL code

select * from t_test t
where not exists(select 1 from t_test where t_time>t.t_time and t_num=t.t_num)

------解决方案--------------------

SQL code
select
 * 
from
 t_test t
where
 not exists(select 1 from t_test where t_time>t.t_time and t_num=t.t_num)
--
或者

select
 * 
from
 t_test t
where
 t_time=(select max(t_time) from t_test where t_num=t.t_num)