日期:2014-05-17  浏览次数:20776 次

有点类似行转列的统计
数据格式如下:
cid total date
1 10 2011-12
1 34 2012-04
2 15 2011-10
2 45 2011-12
2 14 2012-05
3 25 2011-11
4 64 2011-10
4 25 2011-12
4 34 2012-03

我要查询从2011-10到2012-05这个时间段的各CID的total是多少,结果如下:

cid 2011-10 2011-11 2011-12 2012-01 2012-02 2012-03 2012-04 2012-05
1 0 0 10 0 0 0 34 0
2 15 0 45 0 0 0 0 14
3 0 25 10 0 0 0 0 0
4 64 0 25 0 0 34 0 0

这样的统计该如何写?
SQL2008

------解决方案--------------------
SQL code

create table ing
(cid int, total int, datem varchar(10))

insert into ing
select 1, 10, '2011-12' union all
select 1, 34, '2012-04' union all
select 2, 15, '2011-10' union all
select 2, 45, '2011-12' union all
select 2, 14, '2012-05' union all
select 3, 25, '2011-11' union all
select 4, 64, '2011-10' union all
select 4, 25, '2011-12' union all
select 4, 34, '2012-03'


declare @startdate varchar(8),
        @enddate varchar(8),
        @sql varchar(6000)

select @startdate='2011-10', -- 开始时间
       @enddate='2012-05',   -- 结束时间
       @sql='select cid,'

select @sql=@sql+'max(case when datem='''+datem+''' then total else 0 end) '''+datem+''', '
from (select distinct datem from ing where cast(datem+'-01' as date)
      between @startdate+'-01' and @enddate+'-01') t
order by datem

select @sql=left(@sql,len(@sql)-1)+
' from ing
  where cast(datem+''-01'' as date) 
  between '''+@startdate+'-01'' and '''+@enddate+'-01''
  group by cid'
  
exec(@sql)  

/*
cid         2011-10     2011-11     2011-12     2012-03     2012-04     2012-05
----------- ----------- ----------- ----------- ----------- ----------- -----------
1           0           0           10          0           34          0
2           15          0           45          0           0           14
3           0           25          0           0           0           0
4           64          0           25          34          0           0

(4 row(s) affected)
*/

------解决方案--------------------
pivot方案
SQL code

if OBJECT_ID('tempdb..#test') is not null
    drop table #test
create table #test (cid int, total int, datem varchar(10))

insert into #test
select 1, 10, '2011-12' union all
select 1, 34, '2012-04' union all
select 2, 15, '2011-10' union all
select 2, 45, '2011-12' union all
select 2, 14, '2012-05' union all
select 3, 25, '2011-11' union all
select 4, 64, '2011-10' union all
select 4, 25, '2011-12' union all
select 4, 34, '2012-03'

declare @mthList varchar(max)
select @mthList=coalesce(@mthList + ',','')+'['+datem+']' from 
(select distinct datem from #test where datem between '2011-10' and '2012-05')a

set @mthList='
select * from #test
pivot 
    (sum(total) for datem in (' + @mthList +')) b'
print @mthList
exec(@mthList)

cid    2011-10    2011-11    2011-12    2012-03    2012-04    2012-05
1    NULL    NULL    10    NULL    34    NULL
2    15    NULL    45    NULL    NULL    14
3    NULL    25    NULL    NULL    NULL    NULL
4    64    NULL    25    34    NULL    NULL