日期:2014-05-17  浏览次数:20635 次

3表关联,求正确的sql
表forum
字段fno
1
2
3
4
表board
字段bno,字段fno
1      1
2      2
3      3
4      4
5      2
表user
字段uno,字段fno
1      1
2      2
3      3
4      4
5      1

3个表都是与字段fno关联,表board与表user计算总数ct1和ct2,得到的结果是:
fno name url pr br ct1 ct2 remark
1           1  2
2           2   1
3           1  1
4           1   1

这是我写的sql可是有错误:
sql_str = "select F.fno,F.name,F.url,F.pr,F.br,isnull(count(B.bno),0) as ct1,isnull(count(U.uno),0) as ct2,F.remark from forum F left outer join board B on F.fno = B.fno left outer join [user] U on F.fno = U.fno group by F.fno,F.name,F.url,F.pr,F.br,F.remark order by F.fno desc";

我得到的错误结果是:
fno name url pr br ct1 ct2 remark
1           2  2
2           2  2
3           1  1
4           1  1

求正确的写法。

------解决方案--------------------
SQL code
select a.fno,a.ct1,b.ct2 from 
(
    select F.fno,isnull(count(B.bno),0) as ct1
    from forum F 
    left join board B 
    on F.fno = B.fno 
    group by F.fno
) a,
(
    select F.fno,isnull(count(U.uno),0) as ct2
    from forum F 
    left join [user] U 
    on F.fno = U.fno 
    group by F.fno    
) b
where a.fno=b.fno

------解决方案--------------------
SQL code

--> 测试数据: @forum
declare @forum table (fno int)
insert into @forum
select 1 union all
select 2 union all
select 3 union all
select 4

--> 测试数据: @board
declare @board table (bno int,fno int)
insert into @board
select 1,1 union all
select 2,2 union all
select 3,3 union all
select 4,4 union all
select 5,2

--> 测试数据: @user
declare @user table (uno int,fno int)
insert into @user
select 1,1 union all
select 2,2 union all
select 3,3 union all
select 4,4 union all
select 5,1

select * ,
(select count(1) from @board where fno=a.fno) as ct1 ,
(select count(1) from @user where fno=a.fno) as ct2
from @forum a
/*
fno         ct1         ct2
----------- ----------- -----------
1           1           2
2           2           1
3           1           1
4           1           1
*/

------解决方案--------------------
SQL code

select F.fno,F.name,F.url,F.pr,F.br,B.cou,U.cou,F.remark
from forum F
left join (select fno,count(1) cou from board group by fno) B on F.fno = B.fno
left join (select fno,count(1) cou from [user] group by fno) U on F.fno = U.fno