select 日期,count(*) as 品种数,
    sum(case when 价格 >= 10 then 1 else 0 end) as 大于等于10品种数
from tb
group by 日期

------解决方案--------------------
SQL code

--> 测试数据：@T
declare @T table([日期] datetime,[品种] varchar(1),[价格] int)
insert @T
select '2012/1/1','a',8 union all
select '2012/1/1','b',7 union all
select '2012/1/1','c',11 union all
select '2012/1/1','d',12 union all
select '2012/1/1','e',9 union all
select '2012/1/1','f',10 union all
select '2012/1/1','g',13 union all
select '2012/1/2','a',11 union all
select '2012/1/2','b',9 union all
select '2012/1/2','c',8 union all
select '2012/1/2','d',7 union all
select '2012/1/2','e',10 union all
select '2012/1/2','f',11 union all
select '2012/1/3','a',10 union all
select '2012/1/3','b',11 union all
select '2012/1/3','c',9 union all
select '2012/1/3','d',11 union all
select '2012/1/3','e',12 union all
select '2012/1/3','f',8 union all
select '2012/1/3','g',7 union all
select '2012/1/3','h',9 union all
select '2012/1/3','i',10 union all
select '2012/1/3','j',12 union all
select '2012/1/3','k',8

select 
    日期,
    count(1) as 品种数,
    sum(case when 价格>10 then 1 else 0 end) as 大于等于10元品种数
from @T group by 日期
/*
日期                      品种数         大于等于10元品种数
----------------------- ----------- -----------
2012-01-01 00:00:00.000 7           3
2012-01-02 00:00:00.000 6           2
2012-01-03 00:00:00.000 11          4
*/