日期:2014-05-18  浏览次数:20566 次

[SQL]请各位大侠指点帮助,卡住了:(
Name Status Data
a Pass 2012-05-12
a Pass 2012-05-11
a Fail 2012-05-09
a Pass 2012-05-10
b Pass 2012-05-12
b Fail 2012-05-11
b Pass 2012-05-10
b Pass 2012-05-09
b Pass 2012-05-08
c Pass 2012-05-09
c Pass 2012-05-12
d Pass 2012-05-09
d Pass 2012-05-08
e Pass 2012-05-12
e Pass 2012-05-11
e Pass 2012-05-09
w Pass 2012-05-12
w Fail 2012-05-12
y Pass 2012-05-12
y Fail 2012-05-11
y Fail 2012-05-09
y Fail 2012-05-06
y Fail 2012-05-05
z Fail 2012-05-06
z Fail 2012-05-05
1.根据该表查询出“最近”两次状态都是Pass的名字?
(预期结果)查询结果如下:

c
d
e
2.根据该表查询出“最近”的两次状态中,最近的一次是Pass ,另一个为Fail
(预期结果)查询结果如下:
b
w
y

------解决方案--------------------
SQL code
if object_id('[tb]') is not null drop table [tb]
go
create table [tb]([Name] varchar(1),[Status] varchar(4),[Data] datetime)
insert [tb]
select 'a','Pass','2012-05-12' union all
select 'a','Pass','2012-05-11' union all
select 'a','Fail','2012-05-09' union all
select 'a','Pass','2012-05-10' union all
select 'b','Pass','2012-05-12' union all
select 'b','Fail','2012-05-11' union all
select 'b','Pass','2012-05-10' union all
select 'b','Pass','2012-05-09' union all
select 'b','Pass','2012-05-08' union all
select 'c','Pass','2012-05-09' union all
select 'c','Pass','2012-05-12' union all
select 'd','Pass','2012-05-09' union all
select 'd','Pass','2012-05-08' union all
select 'e','Pass','2012-05-12' union all
select 'e','Pass','2012-05-11' union all
select 'e','Pass','2012-05-09' union all
select 'w','Pass','2012-05-12' union all
select 'w','Fail','2012-05-12' union all
select 'y','Pass','2012-05-12' union all
select 'y','Fail','2012-05-11' union all
select 'y','Fail','2012-05-09' union all
select 'y','Fail','2012-05-06' union all
select 'y','Fail','2012-05-05' union all
select 'z','Fail','2012-05-06' union all
select 'z','Fail','2012-05-05'
go

select name
from
(
  select * from tb t 
  where data in(select top 2 data from tb where name=t.name order by data desc)
) t
where status='pass'
group by name
having count(1)>1
/**
name
----
a
c
d
e

(4 行受影响)
**/

select name
from
(
  select * from tb t 
  where data in(select top 2 data from tb where name=t.name order by data desc)
) t
group by name
having count(distinct status)>1
/**
name
----
b
w
y

(3 行受影响)
**/

------解决方案--------------------
create table t1
(
name varchar(2),
sta varchar(5),
data date
)
insert into t1
select 'a','Pass','2012-05-12' union all
select 'a','Pass','2012-05-11' union all
select 'a','Fail','2012-05-09' union all
select 'a','Pass','2012-05-10' union all
select 'b','Pass','2012-05-12' union all
select 'b','Fail','2012-05-11' union all
select 'b','Pass','2012-05-10' union all
select 'b','Pass','2012-05-09' union all
select 'b','Pass','2012-05-08' union all
select 'c','Pass','2012-05-09' union all
select 'c','Pass','2012-05-12' union all
select 'd','Pass','2012-05-09' union all
select 'd','Pass','2012-05-08' union all
select 'e','Pass','2012-05-12' union all
select 'e','Pass','2012-05-11' union all
select 'e','Pass','2012-05-09' union all
select 'w','Pass','2012-05-12' union all
select 'w','Fail','2012-05-12' union all
select 'y','Pass','2012-05-12' union all
select 'y','Fail','2012-05-11' union all
select 'y','Fail','2012-05-09' union all
select 'y','Fail','2012-05-06' union all
select 'y','Fail','2012-05-05' union all
select 'z','Fail','2012-05-06' union all
select 'z','Fail','2012-05-05'
select * from t