日期:2014-05-18 浏览次数:20500 次
with cte as ( select *, row_number() over( order by getdate()) as id from ( select 住宿名单1 as col from tb union all select 住宿名单2 from tb union all select 住宿名单3 from tb union all select 住宿名单4 from tb ) as t ) select * from cte as a where exists ( select * from cte as b where a.col = b.col and a.id <> b.id )