日期:2014-05-18 浏览次数:20598 次
WITH lmenu(name,senior,level) as ( SELECT NAME,SENIOR,0 level FROM MENU WHERE SENIOR IS NULL UNION ALL SELECT A.NAME,A.SENIOR,b.level+1 FROM MENU A,lmenu b where a.senior = b.name ) SELECT * from lmenu --你这个是递归吗? 给你一个递归的例子,最基础的递归: --> 测试数据:[tbl] go if object_id('[tbl]') is not null drop table [tbl] go create table [tbl]( [name] varchar(1), [date] varchar(5), [num] int ) go insert [tbl] select 'a','1-1号',1 union all select 'b','1-2号',4 union all select 'a','1-3号',8 union all select 'a','1-4号',5 union all select 'b','1-5号',6 union all select 'b','1-6号',9 ;with t as( select ROW_NUMBER()over(partition by name order by [date]) as id, *,num as total from tbl ), m as( select id,name,[date],num,total from t where id=1 union all select a.id,a.name,a.[date],a.num,b.total+a.num from t a inner join m b on a.id=b.id+1 and a.name=b.name ) select name,[date],num,total from m order by name /* name date num total a 1-3号 8 8 a 1-4号 5 13 a 1-1号 1 14 b 1-2号 4 4 b 1-5号 6 10 b 1-6号 9 19 */