日期:2014-05-18  浏览次数:20475 次

sql split查询
wb
ID QuestionClassification
a 1,2,3,4,5,6,7
b 11,22,33,44,55,66,77
c 111,222,333,444,555,666,777

wu
id name KeyWord
1 aa 1,22,333
2 bb 111,1,22
3 cc 22,33


select QuestionClassification from wb where ID='a'
我从wb中查到的数据 1,2,3,4,5,6,7


怎么才能通过我查到的1,2,3,4,5,6,7(以,格开进行查询)

因为id 1和2 的KeyWord包含 1,2,3,4,5,6,7中的1
所以怎么从表 wu 中查出
1 aa 1,22,333
2 bb 111,1,22


------解决方案--------------------
SQL code
if object_id('[wb]') is not null drop table [wb]
go
create table [wb]([ID] varchar(1),[QuestionClassification] varchar(27))
insert [wb]
select 'a','1,2,3,4,5,6,7' union all
select 'b','11,22,33,44,55,66,77' union all
select 'c','111,222,333,444,555,666,777'
go
if object_id('[wu]') is not null drop table [wu]
go
create table [wu]([id] int,[name] varchar(2),[KeyWord] varchar(8))
insert [wu]
select 1,'aa','1,22,333' union all
select 2,'bb','111,1,22' union all
select 3,'cc','22,33'
go


select a.* from wu a
join
(
select substring(QuestionClassification,b.number,charindex(',',QuestionClassification+',',b.number)-b.number) as num
 from wb a
join master..spt_values b on b.type='P'  and charindex(',',','+QuestionClassification,b.number)=b.number
where ID='a'
) b
on charindex(','+b.num+',',','+a.keyword+',')>0

/**
id          name KeyWord
----------- ---- --------
1           aa   1,22,333
2           bb   111,1,22

(2 行受影响)
**/

------解决方案--------------------
SQL code

/*
create function [dbo].[m_split](@c varchar(2000),@split varchar(2))    
   returns @t table(col varchar(200))    
   as    
     begin    
       while(charindex(@split,@c) <>0)    
         begin    
           insert @t(col) values (substring(@c,1,charindex(@split,@c)-1))    
             set @c = stuff(@c,1,charindex(@split,@c),'')  
         end    
       insert @t(col) values (@c)    
       return    
 end 
*/

declare @wb table([ID] varchar(1),[QuestionClassification] varchar(27))
insert @wb
select 'a','1,2,3,4,5,6,7' union all
select 'b','11,22,33,44,55,66,77' union all
select 'c','111,222,333,444,555,666,777'

declare @wu table([id] int,[name] varchar(2),[KeyWord] varchar(8))
insert @wu
select 1,'aa','1,22,333' union all
select 2,'bb','111,1,22' union all
select 3,'cc','22,33'

;with maco as
(
select * from [dbo].[m_split]((select [QuestionClassification] from @wb where ID='a'),',')
)

select * from @wu a ,maco b 
where charindex(','+ltrim(b.col)+',',','+a.[KeyWord]+',')>0
/*
id          name KeyWord  col
----------- ---- -------- ------------------------------
1           aa   1,22,333 1
2           bb   111,1,22 1
*/

------解决方案--------------------
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SQL code

/*
create function [dbo].[m_split](@c varchar(2000),@split varchar(2))
returns @t table(col varchar(200))
as
begin
while(charindex(@split,@c) <>0)
……