select 
   姓名,
   max(case px when 1 then 技能 else '' end) as 技能1,
   max(case px when 2 then 技能 else '' end) as 技能2,
   max(case px when 3 then 技能 else '' end) as 技能3
from
   (select px=row_number()over(partition by 姓名 order by getdate()),* from tb)t
group by
    姓名

------解决方案--------------------
探讨


SQL code
select 
   姓名,
   max(case px when 1 then 技能 else '' end) as 技能1,
   max(case px when 2 then 技能 else '' end) as 技能2,
   max(case px when 3 then 技能 else '' end) as 技能3
from
   (select px=row……


------解决方案--------------------

SQL code
----------------------------
-- Author  :fredrickhu(小F，向高手学习)
-- Date    :2012-07-06 13:20:41
-- Version:
--      Microsoft SQL Server 2008 R2 (RTM) - 10.50.1617.0 (Intel X86) 
--    Apr 22 2011 11:57:00 
--    Copyright (c) Microsoft Corporation
--    Enterprise Edition on Windows NT 6.1 <X64> (Build 7600: ) (WOW64)
--
----------------------------
--> 测试数据：[tb]
if object_id('[tb]') is not null drop table [tb]
go 
create table [tb]([姓名] varchar(4),[技能] varchar(4))
insert [tb]
select '张三','C#' union all
select '张三','Java' union all
select '张三','C++' union all
select '李四','PHP' union all
select '李四','C' union all
select '王五','C#'
--------------开始查询--------------------------
declare @sql varchar(8000)
set @sql = 'select 姓名 '
select @sql = @sql + ' , max(case px when ''' + ltrim(px) + ''' then 技能 else '''' end) [技能' + ltrim(px) + ']'
from (select distinct px from  (select px=row_number()over(partition by 姓名 order by getdate()),* from tb)t
) as a
set @sql = @sql + ' from  (select px=row_number()over(partition by 姓名 order by getdate()),* from tb)t
 group by 姓名'
exec(@sql) 
----------------结果----------------------------
/* 姓名   技能1  技能2  技能3
---- ---- ---- ----
李四   PHP  C    
王五   C#        
张三   C#   Java C++

(3 行受影响)

*/

------解决方案--------------------

SQL code

--> 测试数据：[test]
if object_id('[test]') is not null drop table [test]
create table [test]([姓名] varchar(4),[技能] varchar(4))
insert [test]
select '张三','C#' union all
select '张三','Java' union all
select '张三','C++' union all
select '李四','PHP' union all
select '李四','C' union all
select '王五','C#'



select 
    ROW_NUMBER()over(partition by 姓名 order by getdate()) as px,
    * INTO #test
from
    test
declare @str varchar(2000)
set @str=''
select @str=@str+',[技能'+LTRIM(px)+']=max(case when px='+LTRIM(px)
       +' then [技能] else '''' end)'
from #test 
group by px
exec('select [姓名]'+@str+' from #test group by [姓名]')
/*
姓名    技能1    技能2    技能3
李四    PHP    C    
王五    C#        
张三    C#    Java    C++
*/