日期:2014-05-18  浏览次数:20669 次

SQL中的临时表或游标如何循环获得其中的某一条记录?
Declare @Id as integer
  Declare @Id1 as integer
 declare cursor_table cursor for  
  select id from #Data_get1  
  open cursor_table  
  fetch next from cursor_table into @id  
 while(@@fetch_status=0)  
 begin
  set @id1 = @id
  update #Data_get2 set replyzsl = (select count(1) from test where id2=@id1) where id=@id1
 end
  Close cursor_table
  DEALLOCATE cursor_table  

我就是想循环 cursor_table 中的记录,一条一条地循环下来,可以得到每一条记录的id, 用以id 去更新另一个临时表的记录,请帮忙

以上好象不对!请高手指正,谢谢!

------解决方案--------------------
语法没问题
不知道你的逻辑是否正确

------解决方案--------------------
SQL code

while(@@fetch_status=0)   
 begin
  set @id1 = @id
  update #Data_get2 set replyzsl = (select count(1) from test where id2=@id1) where id=@id1
--至少你要加入以下语句避免死循环
   fetch next from cursor_table into @id   
 end

------解决方案--------------------
应该就是少了fetch next from cursor_table into @id
语句导致你不能取到下一条记录。在第一条记录上死循环了
------解决方案--------------------
探讨
应该就是少了fetch next from cursor_table into @id
语句导致你不能取到下一条记录。在第一条记录上死循环了

------解决方案--------------------
SQL code

--楼主可以这样不用 游标,不会锁表,效率也很高

declare @Rows    int,
        @Row    int,
        @ID        int
set @Row = 1
declare @t table(
Row        int identity(1,1)    not null,
Id        int                    not null
)

insert into @t
select id from  #Data_get1 
set @Rows = @@ROWCOUNT
while(@Row <=@Rows)
begin
    select @id = id from @t where Row = @Row
    update #Data_get2 set replyzsl = (select count(1) from test where id2=@id) where id=@id
    set @row = @row + 1
end