declare @t table (ID varchar(1),userName varchar(5),parentId varchar(1),status bit)
insert into @t
select 1,'user1',0,1 union all
select 2,'user2',1,1 union all
select 3,'user3',2,0 union all
select 4,'user4',3,0 union all
select 5,'user5',1,1 union all
select 6,'user6',5,0

Declare @p varchar(6) set @p='user1'

select id,userName from @T 
where parentId=(select id from @T where userName=@p)
/*
id   userName
---- --------
2    user2
5    user5
*/

--不知道后面的 2 2 1 1 是怎么统计出来的...

--深度排序显示处理
DECLARE @t_Level TABLE(ID char(3),Level int,Sort varchar(8000))
DECLARE @Level int
SET @Level=0
INSERT @t_Level SELECT ID,@Level,ID
FROM @t
WHERE parentId =0
WHILE @@ROWCOUNT>0
BEGIN
    SET @Level=@Level+1
    INSERT @t_Level SELECT a.ID,@Level,b.Sort+a.ID
    FROM @t a,@t_Level b
    WHERE a.parentId=b.ID
        AND b.Level=@Level-1
END

--显示结果
SELECT left(SPACE(b.Level*2)+'|--'+a.userName,16) as userName,a.status
FROM @t a,@t_Level b WHERE a.ID=b.ID ORDER BY b.Sort
/*
userName                         status
-------------------------------- ------
|--user1                         1
  |--user2                       1
    |--user3                     0
      |--user4                   0
  |--user5                       1
    |--user6                     0
*/

--你给出的结果：user2后面是2真2假 
--user5后面是1真1假
--一共是6个数据，但是user1的真为什么算到2里面？