日期:2014-05-18  浏览次数:20664 次

SQL查询合并查询列的问题

假设我有一个表是上图的样子,我想实现group by on_tick_sellnumber_str 的效果,就是说按找这个列来合并最后两列的产品及数量,合并后的样子应是下面的样子,请大家指点一下有没有好的办法呢

on_tick_sellnumber_str detail(合并后的列名)  
  NH-AX000020 精选年货【5】;特色年货【27】


------解决方案--------------------
SQL code
/*
标题:按某字段合并字符串之一(简单合并)
作者:爱新觉罗.毓华(十八年风雨,守得冰山雪莲花开)
时间:2008-11-06
地点:广东深圳

描述:将如下形式的数据按id字段合并value字段。
id    value
----- ------
1     aa
1     bb
2     aaa
2     bbb
2     ccc
需要得到结果:
id     value
------ -----------
1      aa,bb
2      aaa,bbb,ccc
即:group by id, 求 value 的和(字符串相加)
*/
--1、sql2000中只能用自定义的函数解决
create table tb(id int, value varchar(10))
insert into tb values(1, 'aa')
insert into tb values(1, 'bb')
insert into tb values(2, 'aaa')
insert into tb values(2, 'bbb')
insert into tb values(2, 'ccc')
go

create function dbo.f_str(@id int) returns varchar(100)
as
begin
    declare @str varchar(1000)
    set @str = ''
    select @str = @str + ',' + cast(value as varchar) from tb where id = @id
    set @str = right(@str , len(@str) - 1)
    return @str
end
go

--调用函数
select id , value = dbo.f_str(id) from tb group by id

drop function dbo.f_str
drop table tb


--2、sql2005中的方法
create table tb(id int, value varchar(10))
insert into tb values(1, 'aa')
insert into tb values(1, 'bb')
insert into tb values(2, 'aaa')
insert into tb values(2, 'bbb')
insert into tb values(2, 'ccc')
go

select id, [value] = stuff((select ',' + [value] from tb t where id = tb.id for xml path('')) , 1 , 1 , '')
from tb
group by id

drop table tb


--3、使用游标合并数据
create table tb(id int, value varchar(10))
insert into tb values(1, 'aa')
insert into tb values(1, 'bb')
insert into tb values(2, 'aaa')
insert into tb values(2, 'bbb')
insert into tb values(2, 'ccc')
go
declare @t table(id int,value varchar(100))--定义结果集表变量
--定义游标并进行合并处理
declare my_cursor cursor local for
select id , value from tb
declare @id_old int , @id int , @value varchar(10) , @s varchar(100)
open my_cursor
fetch my_cursor into @id , @value
select @id_old = @id , @s=''
while @@FETCH_STATUS = 0
begin
    if @id = @id_old
       select @s = @s + ',' + cast(@value as varchar)
    else
      begin
        insert @t values(@id_old , stuff(@s,1,1,''))
        select @s = ',' + cast(@value as varchar) , @id_old = @id
      end
    fetch my_cursor into @id , @value
END
insert @t values(@id_old , stuff(@s,1,1,''))
close my_cursor
deallocate my_cursor

select * from @t
drop table tb

------解决方案--------------------
行列转换

select on_tick_sellnumber_str ,精选年货=sum(case 倒数第二列的列名 when '精品年货' then exp end),
特色年货=sum(case 倒数第二列的列名 when '特色年货' then exp end)
from tb
group by on_tick_sellnumber_str
------解决方案--------------------
http://blog.csdn.net/happy664618843/archive/2010/03/05/5350835.aspx 参考
------解决方案--------------------
SQL code
create table on_tick(
    on_tick_sellnumber_str  nvarchar(256),
    ticktype_name_des nvarchar(256),
    expr2 int
)

insert into on_tick values(N'NH-AX000020', N'精选年货', 5)
insert into on_tick values(N'NH-AX000020', N'特色年货', 27)

insert into on_tick values(N'NH-AX000021', N'精选年货', 1)
insert into on_tick values(N'NH-AX000021', N'特色年货', 2)

select on_tick_sellnumber_str,'精选年货'=sum(case ticktype_name_des when '精选年货' then expr2 end),
'特色年货'=sum(case ticktype_name_des when '特色年货' then expr2 end)
from on_tick
group by on_tick_sellnumber_str

------解决方案--------------------
dawugui 给出的就很全面了。支持1楼。
------解决方案--------------------
SQL code
应该是字符串的合并
select
 on_tick_sellnumber_str ,
 [ticketype_name_dec] = stuff((select ',' + [ticketype_name_dec] from tb t where on_tick_sellnumber_str  = tb.on_tick_sellnumber_str  for xml path('')) , 1 , 1 , '')
from
 tb
group by
 on_tick_sellnumber_s