日期:2014-05-18 浏览次数:20347 次
select top(1) stu_score from (select top(2) stu_score from tb_score where course_id= (select course_id from tb_course where course_name = 'java') order by stu_score Desc ) order by stu_score ASC
select top(1) stu_score from (select top(2) stu_score from tb_score where course_id= (select course_id from tb_course where course_name = 'java') order by stu_score Desc --这样选出来的是倒数第二句的成绩) order by stu_score ASC --#1. select top(1) stu_score from (select top(2) stu_score from tb_score where course_id= (select course_id from tb_course where course_name = 'java') order by stu_score asc) T order by stu_score desc --#2. select * from ( select rowno = row_number() over(order by a.stu_score), * from tb_score a inner join tb_course b on a.course_id = b.course_id where b.course_name = 'java' ) T where rowno = 2