declare @x int=1,@y int,@c varchar(6000)
while(@x<=9)
begin
 select @y=1,@c=''
 while(@y<=@x)
 begin
   select @c=@c+cast(@y as varchar)+'x'+cast(@x as varchar)+'='+cast(@x*@y as varchar)+' '
   select @y=@y+1
 end
 print @c+char(10)
 select @x=@x+1
end

/*
1x1=1 

1x2=2 2x2=4 

1x3=3 2x3=6 3x3=9 

1x4=4 2x4=8 3x4=12 4x4=16 

1x5=5 2x5=10 3x5=15 4x5=20 5x5=25 

1x6=6 2x6=12 3x6=18 4x6=24 5x6=30 6x6=36 

1x7=7 2x7=14 3x7=21 4x7=28 5x7=35 6x7=42 7x7=49 

1x8=8 2x8=16 3x8=24 4x8=32 5x8=40 6x8=48 7x8=56 8x8=64 

1x9=9 2x9=18 3x9=27 4x9=36 5x9=45 6x9=54 7x9=63 8x9=72 9x9=81 
*/

declare @a smallint,
        @b smallint,
        @str varchar(1000)
set @a=1
while @a<=9
begin
    set @b=1
    set @str=''
    while @b<=@a
    begin
        select @str=@str+convert(varchar(1),@b)+'*'+convert(varchar(1),@a)+'='+convert(varchar(2),@a*@b)+space(2)
        set @b=@b+1
    end
    print @str
    set @a=@a+1
end

------解决方案--------------------
SQL code

declare @x int
declare @y int
declare @c varchar(6000)
set @x = 1
while(@x<=9)
begin
 select @y=1,@c=''
 while(@y<=@x)
 begin
   select @c=@c+cast(@y as varchar)+'x'+cast(@x as varchar)+'='
        +(case when len(ltrim(@x*@y))>1 then '' else ' ' end)+ltrim(@x*@y)+' '
   select @y=@y+1
 end
 print @c+char(10)
 select @x=@x+1
end

/*******************************

1x1= 1 

1x2= 2 2x2= 4 

1x3= 3 2x3= 6 3x3= 9 

1x4= 4 2x4= 8 3x4=12 4x4=16 

1x5= 5 2x5=10 3x5=15 4x5=20 5x5=25 

1x6= 6 2x6=12 3x6=18 4x6=24 5x6=30 6x6=36 

1x7= 7 2x7=14 3x7=21 4x7=28 5x7=35 6x7=42 7x7=49 

1x8= 8 2x8=16 3x8=24 4x8=32 5x8=40 6x8=48 7x8=56 8x8=64 

1x9= 9 2x9=18 3x9=27 4x9=36 5x9=45 6x9=54 7x9=63 8x9=72 9x9=81

------解决方案--------------------
9*9乘法表？

------解决方案--------------------
SQL code
select
max(case when a < 1 then '' else '1*'+cast(a as varchar)+'='+cast(a*1 as varchar)   end)   as   [1],
max(case when a < 2 then '' else '2*'+cast(a as varchar)+'='+cast(a*2 as varchar)   end)   as   [2],
max(case when a < 3 then '' else '3*'+cast(a as varchar)+'='+cast(a*3 as varchar)   end)   as   [3],
max(case when a < 4 then '' else '4*'+cast(a as varchar)+'='+cast(a*4 as varchar)   end)   as   [4],
max(case when a < 5 then '' else '5*'+cast(a as varchar)+'='+cast(a*5 as varchar)   end)   as   [5],
max(case when a < 6 then '' else '6*'+cast(a as varchar)+'='+cast(a*6 as varchar)   end)   as   [6],
max(case when a < 7 then '' else '7*'+cast(a as varchar)+'='+cast(a*7 as varchar)   end)   as   [7],
max(case when a < 8 then '' else '8*'+cast(a as varchar)+'='+cast(a*8 as varchar)   end)   as   [8],
max(case when a < 9 then '' else '9*'+cast(a as varchar)+'='+cast(a*9 as varchar)   end)   as   [9]
from   (
select   1   as   a
union   all
select   2
union   all
select   3
union   all
select   4
union   all
select   5
union   all
select   6
union   all
select   7
union   all
select   8
union   all
select   9
)   as   t1
group   by   a

------解决方案--------------------
元始天尊。

------解决方案--------------------
.....
经典

------解决方案--------------------
在tony哥的博客看到过:
http://blog.csdn.net/htl258/article/details/4013588

------解决方案--------------------