日期:2014-05-18  浏览次数:20477 次

根据子节点 获取它的所有的父节点
表结构如下:

id int 主键

name varchar(50)

parentid int 

id name parentid 

1 a1aa 0

2 bbb 1
3 af 2
4 aff 2
5 aaa 1
6 asa 4

这个分类是无限极,请给出sql 语句,谢谢

------解决方案--------------------
SQL code

-->Title:Generating test data
-->Author:wufeng4552
-->Date :2009-09-30 08:52:38
set nocount on
if object_id('tb','U')is not null drop table tb
go
create table tb(ID int, ParentID int)
insert into tb select 1,0  
insert into tb select 2,1  
insert into tb select 3,1  
insert into tb select 4,2  
insert into tb select 5,3  
insert into tb select 6,5  
insert into tb select 7,6
-->Title:查找指定節點下的子結點
if object_id('Uf_GetChildID')is not null drop function Uf_GetChildID
go
create function Uf_GetChildID(@ParentID int)
returns @t table(ID int)
as
begin
   insert @t select ID from tb where ParentID=@ParentID
   while @@rowcount<>0
   begin
      insert @t select a.ID from tb a inner join @t b
      on a.ParentID=b.id and 
      not exists(select 1 from @t where id=a.id)
   end 
return
end
go
select * from dbo.Uf_GetChildID(5)
/*
ID
-----------
6
7
*/
-->Title:查找指定節點的所有父結點
if object_id('Uf_GetParentID')is not null drop function Uf_GetParentID
go
create function Uf_GetParentID(@ID int)
returns @t table(ParentID int)
as
begin
   insert @t select ParentID from tb where ID=@ID
   while @@rowcount!=0
   begin
     insert @t select a.ParentID from tb a inner join @t b
       on a.id=b.ParentID and 
       not exists(select 1 from @t where ParentID=a.ParentID)
   end
  return
end
go
select * from dbo.Uf_GetParentID(2)
/*
ParentID
-----------
1
0
*/



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------解决方案--------------------
SQL code
;with cte as
(select * from tb where name='asa'
 union all
 select a.* from tb a,cte b where a.id=b.parentid
)
select * from cte order by id

------解决方案--------------------
SQL code
if object_id('[tb]') is not null drop table [tb]
go
create table [tb]([id] int,[name] varchar(4),[parentid] int)
insert [tb]
select 1,'a1aa',0 union all
select 2,'bbb',1 union all
select 3,'af',2 union all
select 4,'aff',2 union all
select 5,'aaa',1 union all
select 6,'asa',4
go

;with cte as
(select * from tb where name='asa'
 union all
 select a.* from tb a,cte b where a.id=b.parentid
)
select * from cte order by id
/**
id          name parentid
----------- ---- -----------
1           a1aa 0
2           bbb  1
4           aff  2
6           asa  4

(4 行受影响)
**/

------解决方案--------------------
SQL code

--> 测试数据:#test
if object_id('tempdb.dbo.#test') is not null drop table #test
create table #test([id] int,[name] varchar(4),[parentid] int)
insert #test
select 1,'a1aa',0 union all
select 2,'bbb',1 union all
select 3,'af',2 union all
select 4,'aff',2 union all
select 5,'aaa',1 union all
select 6,'asa',4


declare @id int
set @id=6
;with t
as(
select * from #test where ID=@id
union all
select a.* from #test a
inner join t b
on a.id=b.parentid
)
select parentid from t
/*
parentid
4
2
1
0
*/