日期:2014-05-18 浏览次数:20366 次
--> 测试数据:[test] if object_id('[test]') is not null drop table [test] create table [test]([ID] int,[VALUE] varchar(1)) insert [test] select 1,'A' union all select 2,'B' union all select 3,'C' union all select 4,'D' select px=ROW_NUMBER()over(order by (select 1)), a.[VALUE]+b.VALUE+c.VALUE as VALUE from test a cross join test b cross join test c where a.VALUE<>b.VALUE and a.VALUE<>c.VALUE and b.VALUE<>c.VALUE /* px VALUE ------------ 1 BAC 2 BAD 3 CAB 4 CAD 5 DAB 6 DAC 7 ABC 8 ABD 9 CBA 10 CBD 11 DBA 12 DBC 13 ACB 14 ACD 15 BCA 16 BCD 17 DCA 18 DCB 19 ADB 20 ADC 21 BDA 22 BDC 23 CDA 24 CDB */