日期:2014-05-18  浏览次数:20499 次

高分求高手: 生成多行序列号
一 、实现的功能要求: 生成多行字符号A-01-001-1到F-99-999-3之间所有的字符串.
  格式如:1位字母-2位数字-3位数字-1位数字  
  说明: 1、1位字母为[A-F]之间 
  2、2位数字[01-99]
  3、3位数字[001-999]
  4、1位数字[1-3]

二、SQL查询时效果如下:
  A-01-001-1 
  A-01-001-2
  A-01-001-3
  A-01-002-1 
  A-01-002-2
  A-01-002-3
  .........
  F-99-999-1
  F-99-999-2
  F-99-999-3



------解决方案--------------------
SQL code
declare @ss varchar(20),@se varchar(100)
select @ss='A-01-001-1',@se='F-99-999-3'

;with sn as
(select top 1000 id=row_number() over(order by getdate()) from sys.objects,sys.columns)

select s1+'-'+s2+'-'+s3+'-'+s4
from
(
select char(ascii(left(@ss,1))+id-1) as s1 from sn
where ascii(left(@ss,1))+id-1<=ascii(left(@se,1))
) t1,
(
select right('00'+ltrim(Parsename(replace(@ss,'-','.'),3)+id-1),2) as s2 from sn
where Parsename(replace(@ss,'-','.'),3)+id-1<=Parsename(replace(@se,'-','.'),3)
) t2,
(
select right('000'+ltrim(Parsename(replace(@ss,'-','.'),2)+id-1),3) as s3 from sn
where Parsename(replace(@ss,'-','.'),2)+id-1<=Parsename(replace(@se,'-','.'),2)
) t3,
(
select ltrim(right(@ss,charindex('-',reverse(@ss))-1)+id-1) s4 from sn
where right(@ss,charindex('-',reverse(@ss))-1)+id-1<=right(@se,charindex('-',reverse(@ss))-1)
) t4

------解决方案--------------------
SQL code


create table a (a_code char(1))
insert a
select 'A' UNION 
SELECT 'B' UNION 
SELECT 'C' UNION
SELECT 'D' UNION
SELECT 'E' UNION
SELECT 'F'

create table b (b_code char(2))
insert b
select convert(varchar(2),right((101+number),2)) from master.dbo.spt_values
where type='P' and number <99

create table c (c_code char(3))
insert c
select convert(varchar(3),right((1001+number),3)) from master.dbo.spt_values
where type='P' and number <999

create table d (id tinyint)
insert d
select number+1 from master.dbo.spt_values
where type='P' and number <3



select a.a_code+'-'+b.b_code+'-'+c.c_code+'-'+convert(varchar(20),d.id) from a cross join b cross join c cross join d
order by a.a_code,b.b_code,c.c_code,d.id
/*
(无列名)
A-01-001-1
A-01-001-2
A-01-001-3
A-01-002-1
A-01-002-2
A-01-002-3
A-01-003-1
A-01-003-2
A-01-003-3
A-01-004-1
...
...
...*/

------解决方案--------------------
C# code

--A-99-999-3

select Code INTO #T0 from
(
    select 'A' as Code UNION 
    SELECT 'B' as Code UNION 
    SELECT 'C' as Code UNION
    SELECT 'D' as Code UNION
    SELECT 'E' as Code UNION
    SELECT 'F' as Code
)a

select top 99  ROW_NUMBER() OVER (order by number)as RowNumber INTO #T1 from master..spt_values 
select top 999  ROW_NUMBER() OVER (order by number)as RowNumber INTO #T2 from master..spt_values 
select top 3  ROW_NUMBER() OVER (order by number)as RowNumber INTO #T3 from master..spt_values 

select 
convert(varchar(20),#T0.Code)+'-'+
convert(varchar(2),right((101+#T1.RowNumber-1),2))+'-'+
convert(varchar(3),right((1001+#T2.RowNumber-1),3))+'-'+
convert(varchar(20),#T3.RowNumber)
from #T0,#T1,#T2,#T3
 
drop table #T0
drop table #T1
drop table #T2
drop table #T3