日期:2014-05-18  浏览次数:20500 次

求大神们帮忙
有一表格数据如下:
  rfid time code run_code
RF12-0000018 2012-04-29 09:41:36 RM4-R01 2
RF12-0000018 2012-04-29 10:39:14 RM4-R01 2
RF12-0000018 2012-04-29 10:53:05 RM4-R01 3
RF12-0000018 2012-04-29 13:24:59 RM4-R01 2
RF12-0000018 2012-04-29 13:43:58 RM4-R01 2
RF12-0000018 2012-04-29 15:33:47 RM4-R01 2
RF12-0000018 2012-04-29 15:52:49 RM4-R01 3

现在想用一条sql语句查找出来的结果如下所示:
  rfid time code run_code
RF12-0000018 2012-04-29 10:39:14 RM4-R01 2
RF12-0000018 2012-04-29 10:53:05 RM4-R01 3
RF12-0000018 2012-04-29 15:33:47 RM4-R01 2
RF12-0000018 2012-04-29 15:52:49 RM4-R01 3

也就是run_code结果为2、3;2、3;当有重复的2出现时只取3前面的最近的2。
不知道大家明白没,求帮忙!!!

------解决方案--------------------
SQL code

--> 测试数据:[test]
if object_id('[test]') is not null 
drop table [test]
create table [test](
[rfid] varchar(12),
[time] datetime,
[code] varchar(7),
[run_code] int
)
insert [test]
select 'RF12-0000018','2012-04-29 09:41:36','RM4-R01',2 union all
select 'RF12-0000018','2012-04-29 10:39:14','RM4-R01',2 union all
select 'RF12-0000018','2012-04-29 10:53:05','RM4-R01',3 union all
select 'RF12-0000018','2012-04-29 13:24:59','RM4-R01',2 union all
select 'RF12-0000018','2012-04-29 13:43:58','RM4-R01',2 union all
select 'RF12-0000018','2012-04-29 15:33:47','RM4-R01',2 union all
select 'RF12-0000018','2012-04-29 15:52:49','RM4-R01',3


with t 
as(
select ROW_NUMBER()OVER(order by getdate()) as px,* from test
)
select [rfid],[time],[code],[run_code] from t a
where exists (select 1 from(
select * from t a where [run_code]=3)b where a.px=b.px or a.px=b.px-1)

/*
rfid    time    code    run_code
RF12-0000018    2012-04-29 10:39:14.000    RM4-R01    2
RF12-0000018    2012-04-29 10:53:05.000    RM4-R01    3
RF12-0000018    2012-04-29 15:33:47.000    RM4-R01    2
RF12-0000018    2012-04-29 15:52:49.000    RM4-R01    3
*/